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kicyunya [14]
3 years ago
7

Help!!!!!!!!!!! Me now!!!!!!!!!!

Mathematics
2 answers:
VMariaS [17]3 years ago
4 0

Answer:

1.225

Step-by-step explanation:

29.6-0.2=29.4

24/29.4=1.225

Zigmanuir [339]3 years ago
3 0

Answer:

29.6 - 0.2 = 29.4

29.4 divided by 24 = 1.225 km

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Write the equation in vertex form of the parabola with the vertex (-4,-4) that goes through the point (-2,-16)
Brrunno [24]

Answer:

- 3(x + 4) {}^{2}  - 4

Step-by-step explanation:

Vertex form is

a(x - h) {}^{2}  + k = f(x)

We know that h and k are both -4. Let x be -2 and y be -16.

a( - 2  + 4) {}^{2}   - 4 =  - 16

a(2) {}^{2}  - 4 =  - 16

4a - 4 =  - 16

4a =  - 12

a =  - 3

So the equation in vertex form is

- 3(x  + 4) {}^{2}  - 4

5 0
2 years ago
What is the total amount of 2/5+5/3+9/3 and the lowest common denominator?
gregori [183]

The lowest common denominator is lcm(5, 3), which is 15.

The sum of 2/5 + 5/3 + 9/3 is 6/15 + 25/15 + 45/15, which is 76/15 or 5\frac{1}{15}.

4 0
3 years ago
PQRS is a parallelogram. PR and QS are diagonals. Match each element to its value. Tiles value of length of value of length of
ss7ja [257]

Since it is a parallelogram cente at point T, then the measure of PT is equal to the measure of TR. And the measure of QT is equal to the measure of TS.

 

PT = TR

a + 4 = 2a

4 = 2a -a

a = 4

 

PT = TR = 8 units

 

QT = TS

b = 2b -3

3 = 2b – b

b = 3

 

<span>QT = TS = 3 units</span>

5 0
3 years ago
Read 2 more answers
Sixty three thousandths in standard form
Hunter-Best [27]

Answer:

sounds like .063 to me

3 0
3 years ago
One pipe can empty a tank 5 times faster than another pipe can fill the tank. Starting with a full tank, if both pipes are turne
xxTIMURxx [149]

Answer:

40 hours

Step-by-step explanation:

Let's say that the slower pipe can fill x amount of the tank in one hour. It adds x amount to the tank every hour. Therefore, we can say, for the slower pipe,

1 hour = x amount

Then, the faster pipe empties the tank 5 times faster than the slower pipe fills it, so it removes 5 times the amount that the smaller pipe puts in, so for the faster pipe,

1 hour = -5x amount (negative to symbolize removing).

For the problem at hand, the tank starts at full, or 100%=1. It ends empty, or at 0% = 0. After 10 hours, if we only account for the slower pipe, we add x amount to the tank every hour, so we add 10 times that total, resulting in

1 + 10 * x as the ending result if we don't include the faster pipe. Then, the faster pipe removes 5x every hour, so in 10 hours, it removes 50x, so we have

1+10 * x - 50 * x as the final amount of stuff in the tank, which is equal to 0. Therefore, we have

1 + 10 * x - 50 * x = 0

1 - 40 * x = 0

add 40*x to both sides to isolate the x and its coefficient

1 = 40 * x

divide both sides by 40 to isolate x

x= 0.025

Therefore, the slower pipe adds 0.025, or 1/40 = 2.5% to the tank every hour. We want to figure out how long it would take for the slower pipe to fill up an empty tank, or turn it from 0% to 100% full.

Because the slower pipe adds 2.5% of the tank every hour, we can say that over y hours, it fills up

2.5% * y amount of the tank. We want to figure out how many hours it would take to make it 100% (we need to add 100% of the tank in the problem), so we can say

2.5% * y = 100%

divide both sides by 2.5% to isolate y

100%/2.5% = y = 40

5 0
3 years ago
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