The value of x is 67°
<u>Step-by-step explanation:</u>
Given that
PN=LN
NP||MQ
QL bisects <PQM
therefore <PQL=<LQM
NP||MQ and NM is a transversal
<PNL+<LMQ=180°(angles on the same side of the transversal are supplementary)
<PNL+54=180°
<PNL=180-54=126°
Consider ΔPNL
since PN=NL,the triangle is isocelus
<NPL=<NLP=a
<NPL+<NLP+<PNL=180°
a+a+126=180°
2a+126=180
2a=180-126
=54°
a=54/2=27°
consider the point L
<NLP+<PLQ+<MLQ=180°
27+70+<MLQ=180
<MLQ=180-97=83°
consider ΔLQM
<LQM+<LMQ+LMQ=180
<LQM+83+54=180
<LQM=180-(83+54)=180-137=43°
<PQL=43°(since<PQL=<LQM)
considerΔPQL
x+70+<PQL=180°
x+70+43=180°
x+113=180
x=180-113
=67°
The value of x is 67°
Answer:
x = 23
Step-by-step explanation:
180 - 42 = 138
138/6 = 23
x = 23
Well, the solid line is y≥x/2-1 whereas the dotted line has the equation
y<4x+1. The solution to this system of inequalities comes out to
being (.8<span>,3.2)</span>
Since , the relation is linear .
Let equation is y = mx + c .
Putting , x = 0 and y = 32 .
32 = c .......( 1 )
Also , putting x = 100 and y = 212 .
We get :
212 = 100m + c .......( 2 )
Comparing equation 1 and 2 .
100m = 212 - 32
x = 1.8
Therefore , y = 1.8x + 32 .
Hence , this is the required solution .
Answer:
x
+
5
Step-by-step explanation:
x
+
5
