I dont know how to this but you probably make 4 3/8 and 2 1/2 into a decimal add all them together...
The temperature of soup after 25 minutes is 
<em><u>Solution:</u></em>
The temperature of chicken soup is 192.7°F
As it cools, the temperature of the soup decreases 2.3°F per minute
Let the initial temperature be 
Let "t" be the time for rate of decrease
Set up an equation
Temperature = Initial temperature - decrease in temperature
Decrease in temperature = rate of decrease x time
Therefore,

<em><u>To find the temperature of soup after 25 minutes, substitute t = 25</u></em>

Thus the temperature of soup after 25 minutes is 
Ht of ceiling = 10 ft which is two-thirds of living rm ceiling
Ht of living rm ceiling = 2/3x = 10 ft
2/3h = 10 ft
2/3h times 3/2 to solve for h = 10 times 3/2
h = 30/2
h = 15 ft
Answer: See the answers below.
The first equation that needs to be solve is: 10 = -16t^2 + 18
If you use the quadratic equation, you will get 0.707 seconds.
For the second equation, you need to solve 0 = -16t^2 + 18.
If you use the quadratic equation, you will get 1.061 seconds.
No, the rate of change is not constant because this is a quadratic equation.
Answer:
1.3 repeating
Step-by-step explanation: