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3 years ago

9

Why does math even exist?

2 answers:

TEA [102]3 years ago

5 0

It does but why do we know the letter x all in favor of getting rid of math say I

natita [175]3 years ago

4 0

I know I dislike it as well! Sorry you are having trouble with it! :)

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HELP BY FIVE MINUTES PLEASE

kati45 [8]

Those are adjacent angles. They equal 180 degrees.

10x-20+6x+8= 180

16x-12=180

Add 12.

16x= 192

x=12

I hope this helps!
~kaikers

6 0

3 years ago

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A man walks iinto a store with 25.50 and walks out with 5.25 how much did he spend?

san4es73 [151]

He spent exactly 20.25, so it's A.

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3 years ago

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For a fruit salad recipe, Jenna combined 3/8 cup of raisins, 7/8 cup of oranges, and 3/4 cup of apples. How many cups of fruit a

Murrr4er [49]

2 cups of fruit salad

8 0

3 years ago

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Find the smaller root for x^2 -9 =-5

Charra [1.4K]

X^2-9=-5
x^2-4=0
(x+2)(x-2)=0 [Difference of Two Squares]
x=-2,2
-2 is the smaller root.

6 0

3 years ago

Solve the following question

nydimaria [60]

9514 1404 393

Answer:

π/3

Step-by-step explanation:

The given integral does not exist. We assume there is a typo in the upper limit, and that you want the integral whose upper limit is (√3)/2.

It is convenient to make the substitution ...

x = sin(y) . . . . so, y = arcsin(x)

dx = cos(y)·dy

Then the integral is ...

$\displaystyle\int_0^{\sqrt{3}/2}{\dfrac{\cos{y}}{\sqrt{1-\sin^2{y}}}}\,dy=\int_0^{\sqrt{3}/2}{dy}=\left.\arcsin{x}\right|\limits_0^{\sqrt{3}/2}\\\\=\arcsin{(\sqrt{3}/2)}=\boxed{\dfrac{\pi}{3}}$

5 0

3 years ago