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3 years ago

Is y=10-x a function?

Mathematics

1 answer:

qaws [65]3 years ago

4 0

Yes it is a function

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Evaluate 5c+cd when c=1/5 and d=15

Ad libitum [116K]

5c = 1
cd = 3
5c + cd = 4

8 0

3 years ago

Read 2 more answers

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago

Pleaseeeee help!!

AnnZ [28]

Las hamburguesas son una comida que se encuentran en un asado.

8 0

3 years ago

How does the value of log Subscript 2 Baseline 100 compare with the value of Log Subscript 6 Baseline 20?.

attashe74 [19]

You can use the change of base formula to get

$\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856$

and also

$\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950$

In general, the change of base formula is

$\log_b(x) = \frac{\log(x)}{\log(b)}$

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2 years ago

A rectangular pool in your friends yard 150 ft. x 400 ft. Create a scale drawing with a scale factor of 1/600 use a table or an

timurjin [86]

Answer:

150 ft. x 400 ft. = 60,000

Step-by-step explanation:

3 0

3 years ago