-5,4
goes to diagonal box on coordinate plane
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Answer:
The estimate of a range of plausible values for the true proportion of people that will not wait more than one minute on hold at a 95% confidence level is
Confidence interval = (549.404, 610.596)
Step-by-step explanation:
We will be finding the confidence interval at 95% confidence level.
The proportion of people that hang up the phone in the first minute of waiting
= P = (580/1000) = 0.58
We can then calculate the standard deviation of the distribution of sample means = σₓ = √[np(1-p)]
where n = sample size = 1000
σₓ = √[np(1-p)] = √[1000×0.58×0.42] = 15.61
Confidence interval = (Sample mean) ± (Margin of error)
Sample mean = 580
Margin of Error = (critical value) × (standard deviation of the distribution of sample means)
Critical value = 1.960
Even though we do not have information on the population mean and standard deviation, we can use the z-distribution's z-score for 95% confidence interval instead of the t-distribution's t-score since the sample size is 1000.
Margin of error = 1.960 × 15.61 = 30.596
Confidence interval = (Sample mean) ± (Margin of error)
Confidence interval = 580 ± 30.596
Confidence interval = (549.404, 610.596)
Hope this Helps!!!
Since the perimeter of the square is 16cm, each side is 4cm.
If we subtract the area of the two unshaded triangles from the area of the square we will know the area of the shaded portion...
The small inverted triangle on the left has a height of 4 and a base of 1. The are of the bottom triangle has a height of 2 and a base of 4...
So the area of the two triangles is 4*1/2+2*4/2=2+4=6
The area of the square is just 4*4=16 so:
The shaded area is 16-6=10cm^2
The proportion of the shaded area to the total area is then:
10cm^2:16cm^2
5:8
Firstly let's find the dimension of this large rectangle:(given)
Area of Rectangle = 660 x 66 =43,560 ft²
And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²
We know that the 20 acres form a rectangle. We need to know what is their disposition:
1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS
Note that W=66 & L=666 = 43,956 ft²/ unit )
lay out shape could be either:(in ft)
1 W by 20 L (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L (Final shape Stacked 132 x 6660 = 879,120) or
4 W by 5 L (Final shape Stacked 264 x 3330 = 879,120) or
2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)
3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.
4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly
