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Hoochie [10]
3 years ago
9

I'm an integer. I am less than zero but greater than -13. When you subtract me from -11. The result is positive. What number am

i?
Mathematics
1 answer:
harina [27]3 years ago
4 0

<u>Answer</u><u>: </u>

Required integer is -12.

Step-by-step explanation:

Given:

Required number is integer.

Required integer is less than zero

greater than -13.

When number is substracted from -11, result is positive.

To Find:

The integer=?

Solution:

Lets assume required integer = x

As Required integer is less than zero and greater than -13 ,  

-13 < x < 0     ------(1)

Also when number is subtracted from -11, result is positive.  

=>  -11 – x > 0

=> -11 > x   -------(2)  

So form 1 and 2  

-13 < x < -11 that is x is an integer which is less than -11 and greater than -13.  There is only one integer between -13 and -11 that is -12.

Hence required integer is -12.

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Answer:

45

Step-by-step explanation:

AEF is a similar triangle to ABC. that means it has the same angles, and the sides (and all other lines in the triangle) are scaled from the ABC length to the AEF length by the same factor f.

now, what is f ?

we know this from the relation of AC to FA.

FA = 12 mm

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so, going from AC to FA we multiply AC by f so that

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f = 12/40 = 3/10

all other sides, heights, ... if ABC translate to their smaller counterparts in AEF by that multiplication with f (= 3/10).

the area of a triangle is

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baseline small = baseline large × f

height small = height large × f

we know that

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8 0
2 years ago
In response to very high demand, a new bike has been marked up by 25% and is now selling for 210.00. how much was the bike befor
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saveliy_v [14]
Rewriting the equation as a quadratic equation equal to zero:
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8 0
3 years ago
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