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Hoochie [10]
3 years ago
9

I'm an integer. I am less than zero but greater than -13. When you subtract me from -11. The result is positive. What number am

i?
Mathematics
1 answer:
harina [27]3 years ago
4 0

<u>Answer</u><u>: </u>

Required integer is -12.

Step-by-step explanation:

Given:

Required number is integer.

Required integer is less than zero

greater than -13.

When number is substracted from -11, result is positive.

To Find:

The integer=?

Solution:

Lets assume required integer = x

As Required integer is less than zero and greater than -13 ,  

-13 < x < 0     ------(1)

Also when number is subtracted from -11, result is positive.  

=>  -11 – x > 0

=> -11 > x   -------(2)  

So form 1 and 2  

-13 < x < -11 that is x is an integer which is less than -11 and greater than -13.  There is only one integer between -13 and -11 that is -12.

Hence required integer is -12.

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a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

Z = \frac{X - \mu}{\sigma}

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b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

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Z = \frac{X - \mu}{s}

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c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

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