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Andrei [34K]
3 years ago
11

How much would you pay for 5 apples at the rate of $6.60 a dozen?

Mathematics
2 answers:
V125BC [204]3 years ago
7 0

Answer:

You would pay $2.75

Step-by-step explanation:

a dozen = 12

6.60 / 12 = $0.55

0.55 x 5 = 2.75

Alex787 [66]3 years ago
4 0

Answer:

$2.75 for 5 apples

Step-by-step explanation:

If I understood correctly, you want the answer to 5 apples at the cost of a dozen.

First, you would need to find the cost of a single apple by dividing the price by the dozen. 6.6/5 = 0.55

Next, you multiply the amount of apples by the cost of a single one. 5 * 0.55 = 2.75

And there you go, hope I helped :)

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The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
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Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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0.1505 = 15.05% probability that the hockey team wins 6 games in November

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3 years ago
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