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3 years ago

What combination of transformations is shown below?

Mathematics

1 answer:

In-s [12.5K]3 years ago

4 0

Answer: Reflection, then rotation.

Step-by-step explanation:

It's the first one because it is reflected as you can see and the it rotates the other way.

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Look at pic 10 points

koban [17]

Answer:

120

Step-by-step explanation: 10 x 12 = 120 m. Hope this helps

7 0

3 years ago

How many integers between 2020 and 2400 have four distinct digits arranged in increasing

ASHA 777 [7]

Answer:

the answer is E

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help please!!!!!!!!!!

Kaylis [27]

B is the answer because you want to do the opposite

3 0

3 years ago

An in-ground pond has the shape of a rectangular prism. The pond has a depth of 24 inches and a volume of 72,000 cubic inches. T

Ksenya-84 [330]

Let
x-------> the length of the pond
y-------> the width of the pond

we know that
[volume of the pond]=area of the base*deep
area of the base=volume/deep
volume=72000 in³
deep=24 in
area of the base=72000/24------> 3000 in²

area of the base=x*y
3000=x*y-------> equation 1
x=2y-----> equation 2

substitute equation 2 in equation 1
3000=[2y]*y------> 2y²=3000-----> y²=1500------> y=38.7 in
x=2y----> x=2*38.7----> x=77.4 in

the answer is
the length of the pond is 77.4 in
the width of the pond is 38.7 in

5 0

3 years ago

The spread of a virus is modeled by V (t) = −t 3 + t 2 + 12t,

VashaNatasha [74]

Functions can be used to model real life scenarios

The reasonable domain is $\mathbf{[0,\infty)}$ .
The average rate of change from t = 0 to 2 is 20 persons per week
The instantaneous rate of change is $\mathbf{V'(t) = -3t^2 + 2t + 12}$ .
The slope of the tangent line at point (2,V(20) is 10
The rate of infection at the maximum point is 8.79 people per week

The function is given as:

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

(a) Sketch V(t)

See attachment for the graph of $\mathbf{V(t) = -t^3 + t^2 + 12t}$

(b) The reasonable domain

t represents the number of weeks.

This means that: t cannot be negative.

So, the reasonable domain is: $\mathbf{[0,\infty)}$

(c) Average rate of change from t = 0 to 2

This is calculated as:

$\mathbf{m = \frac{V(a) - V(b)}{a - b}}$

So, we have:

$\mathbf{m = \frac{V(2) - V(0)}{2 - 0}}$

$\mathbf{m = \frac{V(2) - V(0)}{2}}$

Calculate V(2) and V(0)

$\mathbf{V(2) = (-2)^3 + (2)^2 + 12 \times 2 = 20}$

$\mathbf{V(0) = (0)^3 + (0)^2 + 12 \times 0 = 0}$

So, we have:

$\mathbf{m = \frac{20 - 0}{2}}$

$\mathbf{m = \frac{20}{2}}$

$\mathbf{m = 10}$

Hence, the average rate of change from t = 0 to 2 is 20

(d) The instantaneous rate of change using limits

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

The instantaneous rate of change is calculated as:

$\mathbf{V'(t) = \lim_{h \to \infty} \frac{V(t + h) - V(t)}{h}}$

So, we have:

$\mathbf{V(t + h) = (-(t + h))^3 + (t + h)^2 + 12(t + h)}$

$\mathbf{V(t + h) = (-t - h)^3 + (t + h)^2 + 12(t + h)}$

Expand

$\mathbf{V(t + h) = (-t)^3 +3(-t)^2(-h) +3(-t)(-h)^2 + (-h)^3 + t^2 + 2th+ h^2 + 12t + 12h}$ $\mathbf{V(t + h) = -t^3 -3t^2h -3th^2 - h^3 + t^2 + 2th+ h^2 + 12t + 12h}$