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11111nata11111 [884]
2 years ago
11

Which of the following processes relies directly on the complementary base pairing of nucleotides?

Biology
2 answers:
KatRina [158]2 years ago
5 0

Answer:

B. replication of DNA

Explanation:

Ksju [112]2 years ago
4 0

Answer:

B. replication of DNA

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Why do some codons code for the same
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Explanation: Multiple different combinations of bases (A, G, C, T) can code for the same amino acid. This means that there are more possible combinations of the bases than there are amino acids. There are 20 amino acids and the four bases can have up to 64 different codon combinations.
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Iron-55 has a half-life of 3 years. How much of a 40 gram sample will remain after 12 years? A. 0 grams B. 4 grams C. 2.5 grams
Readme [11.4K]

Answer:

\boxed {\boxed {\sf C. \ 2.5 \ grams }}

Explanation:

We are asked to find how much of a 40 gram sample remains after 12 years.

Iron-55 has a half-life of 3 years. Therefore, after 12 years, 4 half-lives have been completed.

  • 12 years/3 years = 4 half-lives

Every time a half-life is completed, half of the sample's mass decays. Remember we start with a 40 gram sample.

  • 1 half- life: 40 g / 2 = 20 g
  • 2 half-lives: 20 g / 2= 10 g
  • 3 half-lives: 10 g / 2 = 5 g
  • 4 half-lives: 5 g / 2 = 2.5 g

There is also a formula that can be used to solve this problem.

A= A_o(\frac {1}{2})^{\frac{t}{hl}

Where A₀ is the initial amount, t is the time, and hl is the half-life.

We know 40 grams is the inital amount, 12 years is the time, and 3 years is the halflife.

  • A₀= 40 g
  • t= 12
  • hl= 3

A= 40 \ g (\frac{1}{2})^\frac{12}{3}

A= 40 \ g (\frac{1}{2})^4

A= 40 \ g * 0.0625

\bold {A= 2.5 \ g}

After 12 years, <u>2.5 grams </u> of Iron-55 will remain.

4 0
2 years ago
Is pawpaw a local food crop
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Pawpaw means papaya. Hope you'll get some clues from here

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Name classifications of matter used In the 1800
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The choices can be found elsewhere and as follows:

<span>atural and synthetic
metabolites and nonmetabolites
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organic compounds and inorganic compounds

I think the correct answer from the choices is the third option. The c</span>lassifications of matter used In the 1800 are proteins, carbohydrates, lipids, and nucleic acids. Hope this helps.
8 0
3 years ago
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