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Otrada [13]
3 years ago
14

The picture is above I’ll mark as brainliest.

Mathematics
2 answers:
Kaylis [27]3 years ago
8 0

Answer: ?=5

Step-by-step explanation:

In a rectangle the opposite sides are congruent (same length).

So we have ?+?+3+3=16

Let's use a variable for ?

x+x+3+3=16

Since there are 2 of the variable x we can write it as 2x since 2 of something means it's doubled. We can also combine 3 and 3.

2x+6=16

Let's subtract 6 from both sides.

2x+6-6=16-6\\2x=10

Now let's divide both sides by 2 to find the value of x (which is ?)

\frac{2x}{2} =\frac{10}{2} \\x=5

The value of x/? is 5.

Oksana_A [137]3 years ago
3 0

Answer:

?=5

Step-by-step explanation:

So let's do 16-6 (3*2)

10/2=5

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Solve the formula C= 3.14*d ?
gavmur [86]

Answer: d=\frac{50C}{157}

Step-by-step explanation:

C=3.14d

3.14d=C

3.14d\cdot \:100=C\cdot \:100

314d=C\cdot \:100

\frac{314d}{314}=\frac{C\cdot \:100}{314}

d=\frac{50C}{157}

7 0
3 years ago
A radioactive substance decays at a continuous rate of 17% per year, and 250 mg of the substance is present in the year 2009.
yaroslaw [1]

Answer:

a) A(t) = 250 (1-0.17)^t = 250(0.83)^t

b) A(t=14) = 250 (0.83)^{14}= 18.408 mg

c) For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

Step-by-step explanation:

Part a

For this case we know that the decay rate per year is about 17% or 0.17 in fraction and the initial amount is 250 mg for 2009, we can define the model like this:

A(t) = A_o (1-r)^t

Where A represent the amount of the substance in mg, r the decay rate = 0.17 and t the number of years after 2009.

Our model for this case would be:

A(t) = 250 (1-0.17)^t = 250(0.83)^t

Part b

For this case we have that t= 2023-2009=14 years, so then we can find the amount of substance like this:

A(t=14) = 250 (0.83)^{14}= 18.408 mg

Part c

For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

6 0
3 years ago
5,309 divided by 43 5th grade lesson 2.6
pickupchik [31]
5,309 divided by 43 is equal to 123.4651162790698
7 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL MAKE BRAINLIST
kotykmax [81]

Answer:

22

Step-by-step explanation:

Generate the terms of sequence T using the nth term formula n² - 3

a₁ = 1² - 3 = 1 - 3 = - 2

a₂ = 2² - 3 = 4 - 3 = 1

a₃ = 3² - 3 = 9 - 3 = 6

a₄ = 4² - 3 = 16 - 3 = 13

a₅ = 5² - 3 = 25 - 3 = 22

22 is common to sequence S and T

6 0
3 years ago
.
Westkost [7]

Answer: a

Step-by-step explanation:

5 0
3 years ago
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