Answer:
axis of abscissas
Step-by-step explanation:
Answer:
The solution to the differential equation
y' = 1 + y²
is
y = tan x
Step-by-step explanation:
Given the differential equation
y' = 1 + y²
This can be written as
dy/dx = 1 + y²
Separate the variables
dy/(1 + y²) = dx
Integrate both sides
tan^(-1)y = x + c
y = tan(x+c)
Using the initial condition
y(0) = 0
0 = tan(0 + c)
tan c = 0
c = tan^(-1) 0 = 0
y = tan x
Answer:
u got the right answer in I was just doing this
Answer:
- y = -6
- x=2 and x=6
- Greatest value of y is y=2 and it occurs when x = 4
- For x between x = 2 and x = 6, y > 0
Step-by-step explanation:
<u>Definition</u>
- A parabola is a curve where any point is at an equal distance from:
a fixed point (the focus ), and
a fixed straight line (the directrix )
From the graph we can see that this is indeed so. We can even calculate the parabola equation from the given graph but since that is not required, I am not illustrating the steps here to do that
- The y-intercept is the value of y where the parabola cuts the y axis and from the graph we see that this occurs at y = -6
- The x-intercepts are the x-values where the parabola crosses the x-axis and we can see that this occurs at x = 2 and x = 6
- The greatest value of y occurs at the vertex of the parabola and we see that the vertex is at (4,2) ie greatest value of y is at y = 2 and occurs at x=4
- Between x =2 and x = 6 we see that the y values greater than 0 ie y > 0
(Note on last question: If you exclude these two points then y > 0 between x=2 and x=6.Specifically it is 0 at x =2 and x=6 and > 0. So if you include these two points then y ≥ 0. I have taken it as excluding the two points, x = 2 and x =6)
