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Bezzdna [24]
3 years ago
10

Question : Which Point satisfies the system of equations y= 3x - 2 and y = -2x + 3

Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0

Answer:

D

Step-by-step explanation:

y = 3x - 2 intercepts the y axis at -2

y = -2x + 3 intercepts the y axis at 3

the lines which satisfy these conditions intersect at point D

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What is -5j + j + (-14j) = ?
RUDIKE [14]

Answer:

-18j

Step-by-step explanation:

-5j + j + (-14j)

Factor out a j

j(-5+1-14)

j(-4-14)

j (-18)

-18j

7 0
3 years ago
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hector has found a new horse that he would like to purchase for use around the ranch. his brother, joe, has given him $125 towar
V125BC [204]

the money given by joe to hector is 125$

let the hector works for x weeks,

it is given that hector earns 50$ in a week,

so the total money hector wants to save is 1100$

now

1100=50x+125

from the above inequality, we will find x

\begin{gathered} 1100-125=50x \\ 50x=975 \\ x=19.5 \end{gathered}

it means the hector will work for 20 weeks in order to earn 1100$.

7 0
1 year ago
Simplify 6⁢(3⁢x - 5) + 5⁢(2⁢x - 1).
tatuchka [14]

Answer:

28x-35

Step-by-step explanation:

5 0
3 years ago
In △ABC, point M is the midpoint of AB , point D∈ AC so that AD:DC=2:5. If AABC=56 yd2, find ABMC, AAMD, and ACMD.
Komok [63]

Since point M is the midpoint of AB, then AM=MB.

Consider the area of the triangles ABC and BMC:

A_{ABC}=\dfrac{1}{2}\cdot AB\cdot h_c=56\ yd^2,

where h_c is the height drawn from the vertex C to the side AB.

So, AB\cdot h_c=112\ yd^2.

Now

A_{BMC}=\dfrac{1}{2}\cdot BM\cdot h_c=\dfrac{1}{2}\cdot \dfrac{AB}{2}\cdot h_c=\dfrac{1}{4}\cdot AB\cdot h_c=\dfrac{1}{4}\cdot 112=28\ yd^2.

Also

A_{AMC}=A_{ABC}-A_{BMC}=56-28=28\ yd^2.

Now consider the area of the triangles AMD and CMD. Let h_M be the height drawn from the point M to the side AC.

A_{AMD}=\dfrac{1}{2}\cdot AD\cdot h_M=\dfrac{1}{2}\cdot \dfrac{2AC}{7}\cdot h_M=\dfrac{2}{7}\cdot \left(\dfrac{1}{2}\cdot AC\cdot h_M\right)=\dfrac{2}{7}\cdot A_{AMC}=\dfrac{2}{7}\cdot 28=8\ yd^2.

Therefore,

A_{MDC}=A_{AMC}-A_{AMD}=28-8=20\ yd^2.

Answer: A_{MBC}=28\ yd^2, A_{AMD}=8\ yd^2, A_{MDC}=20\ yd^2.

5 0
3 years ago
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Is the function y = -1.4(0.75)x is an example of exponential growth or decay? Why?
swat32
The best answer is a decay

8 0
3 years ago
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