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Aleks [24]
3 years ago
12

Multiply.

Mathematics
1 answer:
kodGreya [7K]3 years ago
3 0
Solve this by distributing:

-15y⁴-33y³+3y²-24y

It is already in standard form because the degree of each monomial decreases from left to right, so that is your answer.
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Draw a line segment PQ of length 8cm. Find 1/4 of PQ using compass.
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To help you answer:  think about what makes a fourth.  If you have a rectangular cake, how do you split it into four pieces?

To do so with the compass however, remember that the joining the points of intersection of intersecting circles with the same radius creates a perpendicular bisector.
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In ΔABC, if the lengths of sides a and c are 8 centimeters and 16 centimeters, respectively, and the measure of is 35°, what is
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Sin(A)/a= sin(C)/c, therefore sin(A) would = asin(C)/c= sin(35deg)/2. So, A then = arc sin(sin(35deg)/2)= 16.67 
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The sum of three numbers is -44.84. One of the numbers is 26.6. The other two numbers are equal to each other. What is the value
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A+b+c=-44.84

a=26.6
b=c

26.6+b+b=-44.84

2b=-44.84-26.6

b=-35.72


So, a=26.6, b=-35.72, c=-35.72
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3 years ago
WILL GIVE BRAINLIEST!! NEED ANSWERS!! Equations. 1. 4x-2-2x-6= -20
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6 0
3 years ago
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
4 years ago
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