The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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( 30 / 100 ) * (15.40 ) = ( 3 / 10 )* (15.40) = 36.20 / 10 = 3.62$.
<span>3√20/√5
= </span>3 √4 √5<span> / √5
= 3 * 2
= 6
answer is </span><span>b)6</span>
Use a variable to represent the number of hours the technician will work, plus the $50.
50+25x
This would be the expression used to find the amount of money the technician needs.
