Answer:
The line slopes upwards from left to right wit a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2
Step-by-step explanation:
We first rearrange the equation to the order y=mx+c where m is the gradient and c the y intercept.
3y=4x+6
y=(4/3)x+2
The gradient is therefore 4/3 and the y intercept is 2.
At the c intercept, y=0
0=(4/3)x +2
(4/3)x=-2
x=-2×3/4
=3/2
The line slopes upwards from left to right with a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2
Answer:
- vertical asymptote: x = 7
- slant asymptote: y = x+9
Step-by-step explanation:
The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.
There is no horizontal asymptote because the numerator is of higher degree than the denominator.
When you divide the numerator by the denominator, you get ...
y = (x +9) +60/(x -7)
Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.
Let x is the first no. then the other no. will obviously be (x+1)
according to question,
(x+1)²- x²= 15
x² +2x+1 - x² = 15 ( using (a+b)²= a²+ b² + 2ab )
2x + 1 = 15
2x = 14
x = 7
hence numbers are x = 7 and x +1 = 7+1 = 8
also 8²-7² = 64-49 = 15
hence the numbers are 7 and 8
hope it helped