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jolli1 [7]
3 years ago
5

If the cost of 10 tables is $750. Find the number of tables that can be purchased with $8250.

Mathematics
1 answer:
Luden [163]3 years ago
4 0
Your answer is 110. You take 10 and divide it by 750. = 75 then you take 75. Divided 8250. = 110
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You toss a pair of dice. (a determine the number of possible pairs of outcomes. you toss a pair of dice. (a determine the number
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(a) ^{6}C_1 * ^{6}C_1 = 36 different possibilities
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3 0
3 years ago
Can you help me with explanation will give brainiest
Ipatiy [6.2K]

Answer:

Area of rectangular garden = lxb = 10*5

                                             = 50 sq. inch

when area increases by six times

new area = 50*6 = 300 sq inches

now,

let x be increasement in both  length and width

(5+x) (10+x) = 300

50 + 5x + 10x + x² = 300

x² + 15x - 250 = 0

x²+ 25x-10x -250 = 0

x(x+25) - 10 (x+25) = 0

( x-10) (x+25) = 0

either x + 25 =0

x = -25 length can be negative

0r x-10 = 0

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so 10 inches is increase on both side

Step-by-step explanation:

6 0
2 years ago
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scoundrel [369]
The ones with a square in a picture is a 90 degree angle the rest are a 180
7 0
3 years ago
Please help with the question in the picture!
Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

<u>METHOD - I</u>

<u><em>Sin² C + Cos² C = 1</em></u>

Cos² C = 1 - Sin² C

Cos² C = 1 - \frac{9}{25}

Cos² C = \frac{25 - 9}{25}

Cos² C = \frac{16}{25}

Cos C = \sqrt{\frac{16}{25} }

Cos C = \frac{4}{5}

As we know that

Tan C = \frac{Sin C}{Cos C }

<em>Tan C = \frac{\frac{3}{5} }{\frac{4}{5} }</em>

<em>Tan C = \frac{3}{4}</em>

<u>METHOD - II</u>

Given Sin C = \frac{3}{5} = \frac{Height}{Hypotenuse}

therefore,  

AB ( Height ) = 3; BC ( Hypotenuse) = 5

<em>∵ ΔABC is Right triangle.</em>

<em>∴ By Pythagorean Theorem-</em>

<em>AB² + AC² = BC²</em>

<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>

<em>AC² = 5² - 3²</em>

<em>AC² = 25 - 9</em>

<em>AC² = 16</em>

<em>AC  ( Base) = 4</em>

<em>Since, </em>

<em>Tan C = \frac{Height}{Base}</em>

<em>Tan C = \frac{AB}{AC}</em>

<em>Hence Tan C = \frac{3}{4}</em>

<em />

4 0
3 years ago
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