15 is your answer as its 5*3
2n-12n-15=-6n+18-1
-10n-15=-6n+17
+10n. +10n
-15=4n+17
-17. -17
-32=4n
/4 /4
-8=n
53.96+0.17x =57.96+0.12x
0.17x-0.12x=57.96-53.96
0.05x=4.00
x=80 mi
Answer:
(5.240 ; 8.760)
Step-by-step explanation:
Given :
Sample mean, xbar = 7
Standard deviation, s = 2.29
Sample size, n = 9
95% confidence interval for the population mean :
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/sqrt(n)
Tcritical at 0.05 ; df = 8 = 2.306
Margin of Error = 2.306 * 2.29/sqrt(9)
Margin of Error = 1.760
Lower boundary = (7 - 1.760) = 5.240
Upper boundary = (7 + 1.760) = 8.760
(5.240 ; 8.760)