Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
<h3>

</h3>
Answer:
Solution given
Cos
consider Pythagorean theorem

Subtracting
both side

doing square root on both side we get

Similarly

Substituting value of 
we get

<h3>Solving numerical</h3>




Since
In IVquadrant sin angle is negative

Yes is equivalent because 12 x 4 is 48 and 5x5 is 25
X - 17 = -57
-17. -17
x = -74
hope this helps xo