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Anni [7]
3 years ago
7

Which of the points shown below are on the line given by the equation y = 4x?

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0
The answer is (1,4) and (-1,-4)
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Z=Xm+n-p,solve for x
timama [110]

z=xm+n-p

We need to isolate x to one side I will do that on the left side so it looks cleaner, therefore I will first flip the equation.

xm+n-p=z

Now move the n and p to the right side

xm=z-n+p

x=(z-n+p)/m

Hope this helped, if you have any questions about this just comment and I will come answer.

6 0
3 years ago
Solve the equation for principal values of x. Express solutions in degrees.
Hitman42 [59]

Option C:

x = 90°

Solution:

Given equation:

\sin x=1+\cos ^{2} x

<u>To find the degree:</u>

\sin x=1+\cos ^{2} x

Subtract 1 + cos²x from both sides.

\sin x-1-\cos ^{2} x=0

Using the trigonometric identity:\cos ^{2}(x)=1-\sin ^{2}(x)

\sin x-1-\left(1-\sin ^{2}x\right)=0

\sin x-1-1+\sin ^{2}x=0

\sin x-2+\sin ^{2}x=0

\sin ^{2}x+\sin x-2=0

Let sin x = u

u^2+u-2=0

Factor the quadratic equation.

(u+2)(u-1)=0

u + 2 = 0,  u – 1 = 0

u = –2, u = 1

That is sin x = –2, sin x = 1

sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.

sin x = 1

The value of sin is 1 for 90°.

x = 90°.

Option C is the correct answer.

3 0
3 years ago
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The correct answer is B
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Check the picture below.

thus then

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