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Reika [66]
4 years ago
8

Can someone help me with 26 and 27?

Mathematics
1 answer:
Lina20 [59]4 years ago
8 0

Answer:

B

Step-by-step explanation:

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The bottom floor of a parking garage has an elevation of -36 feet. The top floor is 124 feet higher. What is the elevation of th
atroni [7]

88 feet.

I hope this helps :)

8 0
3 years ago
Maria walked 3 km west and 4km south. How far is she from starting point
hjlf

Answer:

if you draw her track and connect her starting and ending points, you have a right triangle, with 3 and 4 being the legs. According to the pythagorean theorem. 3^2+4^2=x^2 when x is her distance from starting point. so x^2=25 and x=5. Her distance is 5

Step-by-step explanation:

8 0
4 years ago
The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as , where a
Andrej [43]
The loudness in decibels is
L = log₁₀(I/I₀)
where
I  = sound intensity, W/m^2
I₀ = reference intensity, = 10^(-12) W/m^2

Raja's power level is 10^(-7) W, therefore the decibel value is
L = 10 log₁₀(10^(-7)/10^(-12))
   = 10log₁₀10^5 
   = 10*5
  = 50 dB

Answer:  50 dB
7 0
4 years ago
Read 2 more answers
20 points and brainliest answer for correct answer
aksik [14]

Answer:

d ( but I really don't know the answer maybe it right

Step-by-step explanation:

right

4 0
3 years ago
Find the inverse of this matrix.<br> 1 -1 -1<br> -1 2 3 <br> 1 1 4
zheka24 [161]

Let's use Gaussian elimination. Consider the augmented matrix,

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right]

• Add row 1 to row 2, and add -1 (row 1) to row 3:

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right]

• Add -2 (row 2) to row 3:

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]

• Add -2 (row 3) to row 2:

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]

• Add row 2 and row 3 to row 1:

\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]

So the inverse is

\begin{bmatrix}1&-1&-1\\-1&2&3\\1&1&4\end{bmatrix}^{-1} = \boxed{\begin{bmatrix}5&3&-1\\7&5&-2\\-3&-2&1\end{bmatrix}}

3 0
4 years ago
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