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1 answer:
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Hey refer to attachment!!!
Draw straight line from 220 (in thousands ) to the plotted line. Draw line parallel to x-axis from point where it touches the plotted line to the y -axis.
It'll automatically meet at 500 which is the answer..
All you need to do is to see the graph carefully.
Hope it helps *_*
Draw straight line from 220 (in thousands ) to the plotted line. Draw line parallel to x-axis from point where it touches the plotted line to the y -axis.
It'll automatically meet at 500 which is the answer..
All you need to do is to see the graph carefully.
Hope it helps *_*
Answer:
3.9 mi/h
Step-by-step explanation:
If the boy is rowing perpendicular to the current, the two vectors form a right triangle.
AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat
AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37
AC = sqrt(15.37) = 3.9 mi/h
The boat's speed over the ground is 3.9 mi/h.
