Answer:
465 ways
Explanation:
Atleast 1 girl and 1 boy
Possible combinations :
1 girl ; 3 boys = 6C1 ; 6C3
2 girls ; 2 boys = 6C2 ; 6C2
3 girls ; 1 boy = 6C3 ; 6C1
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
Combination formula:
nCr = n! ÷ (n-r)!r!
We can also use a calculator :
6C1 = 6
6C3 = 20
6C2 = 15
Hence,
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
(6 * 20) + (15 * 15) + (20 * 6)
120 + 225 + 120
= 465 ways
Answer:
1. List the fields needed to gain information
2. Break down the date into smaller parts
3. identify the fields holding stored data
4.distribute the fields into tables by subject
5. identify the common fields for linking tables
Explanation:
edge 2021
Is this a true or false question? If it is let me know and I can help! (:
Answer:
int main()
{
int number;
printf("Enter a number: ");
scanf_s("%d", &number, sizeof(number));
for (int i = 1; i <= 2; i++) {
printf("%d*%d=%d\n", number, i, number * i);
}
}
Explanation:
I used the safe scanf_s() that takes a third parameter to indicate the size of the buffer. In this case it is the size of an integer.
