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skelet666 [1.2K]
2 years ago
10

Your computer is taking longer than usual to open files and you notice that your hard drive light stays on longer than usual. Wh

ich of the following is a possible solution to counteract this?
Computers and Technology
1 answer:
777dan777 [17]2 years ago
7 0
There might be insufficient storage space so your computer usually takes a longer time to load.The bigger your file, the longer it takes to load. So the solution is to clear up your storage space



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2. Use inheritance to create a hierarchy of Exception classes -- EndOfSentenceException, PunctuationException, and CommaExceptio
Lelechka [254]

Answer:

See explaination

Explanation:

EndOfSentenceException.java

//Create a class EndOfSentenceException that

//extends the Exception class.

class EndOfSentenceException extends Exception

{

//Construtor.

EndOfSentenceException(String str)

{

System.out.println(str);

}

}

CommaException.java

//Create a class CommaException that extends the class

//EndOfSentenceException.

class CommaException extends EndOfSentenceException

{

//Define the constructor of CommaException.

public CommaException(String str)

{

super(str);

}

}

PunctuationException.java

//Create a class PunctuationException that extends the class

//EndOfSentenceException.

class PunctuationException extends EndOfSentenceException

{

//Constructor.

public PunctuationException(String str)

{

super(str);

}

}

Driver.java

//Include the header file.

import java.util.Scanner;

//Define the class Driver to check the sentence.

public class Driver {

//Define the function to check the sentence exceptions.

public String checkSentence(String str)

throws EndOfSentenceException

{

//Check the sentence ends with full stop,

//exclamation mark

//and question mark.

if(!(str.endsWith(".")) && !(str.endsWith("!"))

&& !(str.endsWith("?")))

{

//Check the sentence is ending with comma.

if(str.endsWith(","))

{

//Throw the CommaException.

throw new CommaException("You can't "

+ "end a sentence in a comma.");

}

//Otherwise.

else

{

//Throw PunctuationException.

throw new PunctuationException("The sentence "

+ "does not end correctly.");

}

}

//If the above conditions fails then

//return this message to the main function.

return "The sentence ends correctly.";

}

//Define the main function.

public static void main(String[] args)

{

//Create an object of Scanner

Scanner object = new Scanner(System.in);

//Prompt the user to enter the sentence.

System.out.println("Enter the sentence:");

String sentence=object.nextLine();

//Begin the try block.

try {

//Call the Driver's check function.

System.out.println(new

Driver().checkSentence(sentence));

}

//The catch block to catch the exception.

catch (EndOfSentenceException e)

{}

}

}

5 0
2 years ago
Drag each statement to the correct location.
VMariaS [17]

Answer:

(a)\ 222_{10} = DE_{16} --- True

(b)\ D7_{16} = 11010011_2 --- False

(c)\ 13_{16} = 19_{10} --- True

Explanation:

Required

Determine if the statements are true or not.

(a)\ 222_{10} = DE_{16}

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

DE_{16} = D * 16^1 + E * 16^0

In hexadecimal.

D =13 \\E = 14

So, we have:

DE_{16} = 13 * 16^1 + 14 * 16^0

DE_{16} = 222_{10}

Hence:

(a) is true

(b)\ D7_{16} = 11010011_2

First, convert D7 to base 10 using product rule

D7_{16} = D * 16^1 + 7 * 16^0

D = 13

So, we have:

D7_{16} = 13 * 16^1 + 7 * 16^0

D7_{16} = 215_{10}

Next convert 215 to base 2, using division rule

215 / 2 = 107 R 1

107/2 =53 R 1

53/2 =26 R1

26/2 = 13 R 0

13/2 = 6 R 1

6/2 = 3 R 0

3/2 = 1 R 1

1/2 = 0 R1

Write the remainders from bottom to top.

D7_{16} = 11010111_2

<em>Hence (b) is false</em>

(c)\ 13_{16} = 19_{10}

Convert 13 to base 10 using product rule

13_{16} = 1 * 16^1 + 3 * 16^0

13_{16} = 19

Hence; (c) is true

7 0
2 years ago
Where in an email would u find information about the action requirements​
Assoli18 [71]

Answer:When trying to find the action that you need to do in an e-mail, it is best to consult the body of the email, also known as (B) in the message.. The message would detail the tasks that you need to tackle, which are generally not detailed in the subject line, greeting, and you will most definitely not find in the to field.

Explanation:

3 0
2 years ago
. When attempting to minimize memory usage, the most efficient way to do group processing when using the MEANS procedure is to u
MrRissso [65]

Answer:

A. the BY statement.

Explanation:

The BY statement aids the procedure MEANS to develop the tree for the current BY group only, thereby analyze the stats, and clean the tree prior to the start and development of the next BY group.

However, without the BY statement, procedure MEANS develops its AVL tree for both the whole file and all sector estimates crossings established in CLASS.

Hence, in this case, the correct answer is the BY Statement.

8 0
2 years ago
Is there any website online to use android studio live?​
slavikrds [6]

Answer:

May bhe here

https://developer.android.com/studio/intro

Explanation:

5 0
2 years ago
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