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Alexeev081 [22]
3 years ago
7

6. The following is a dump of a DATA chunk in hexadecimal format. 00000015 00000005 0003000A 00000000 48656C6C 6F000000 a. Is th

is an ordered or unordered chunk? b. Is this the first, the last, the middle, or the only fragment? c. How many bytes of padding are carried by the chunk? d. What is the TSN? e. What is the SI? f. What is the SSN? g. What is the message?
Computers and Technology
1 answer:
ryzh [129]3 years ago
6 0

Answer:

Explanation:

a) taking 00000005, it is a 13th bit which is 0, and therefore, we'd call it an ordered chunk

b) taking 00000005 again, it is 14th (B) and 15th (E) bits are 0 and so we'd call it a middle fragment

c) 00000015 is equal to 21, it is not a multiple of 4, and as such, it needs 3 padding bytes

d) 00000005 is equal to 5 making it a TSN. So the TSN is 5

e) taking 0003, we can then say the SI is 3

f) taking 000A, the SSN is then 10

g) the message is 48656C6C

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Answer:

C. deriving benefits from highly focused and high technology markets

Explanation:

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It should be noted that deriving benefits from highly focused and high technology markets is not part of the approaches to combining overall cost leadership and differentiation competitive advantages.

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3 years ago
Greedy Algorithm Design
Alik [6]

Answer:

The algorithm is as follows:

1. Start

2. Get the number of items (n)

3. Get the current price of the n items (a1, a2..... an)

4. Get the possible hiked price of the n items (b1, b2..... bn)

5. Calculate the difference between the current and hiked prices for each item i.e. d_i = b_i - a_i

6. Sort the differences in descending order (i.e. from the greatest to the least)

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8. Stop

Explanation:

The algorithm is self-explanatory; however, what it does is that:

It takes a list of the current price of items (say list a)

E.g: a = [100, 150, 160]

Then take a list of the hiked price of the items (say list b)

E.g: b = [110, 180, 165]

Next, it calculates the difference (d) between corresponding prices d_i = b_i - a_i

d = [(110 - 100),(180-150),(165-160)]

d = [10,30,5]

Sort the difference from greatest to lowest (as the difference is sorted, lists a and b are also sorted)

d = [30,10,5]

a = [150, 100, 160]

b = [180, 110, 165]

If there is no hike up to item k, the couple would have saved (i = 1 to d[k-1])

Assume k = 3

The couple would have saved for 2 item

Savings = d[1] + d[2]

Savings = 30 +10

Savings = 40

The saved amount will then be added to the kth item in list a i.e. a[k](in this case k = 3) in order to buy b[k]

Using the assumed value of k

a[k] = a[3]

a[3] = 160

b[3] = 165

Add the saved amount (40) to a[3]

New\ Amount = 40 + 160

New\ Amount = 200

This new amount can then be used to buy b[3] i.e. 165, then they save the change for subsequent items

8 0
3 years ago
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Answer:

T

Explanation:

An interface is compiled to a separate bytecode class file.

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class myClass{

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Both of these are compiled to their own respective class files by the compiler,namely, myClass.class and myInterface.class.

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