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Alexeev081 [22]
3 years ago
7

6. The following is a dump of a DATA chunk in hexadecimal format. 00000015 00000005 0003000A 00000000 48656C6C 6F000000 a. Is th

is an ordered or unordered chunk? b. Is this the first, the last, the middle, or the only fragment? c. How many bytes of padding are carried by the chunk? d. What is the TSN? e. What is the SI? f. What is the SSN? g. What is the message?
Computers and Technology
1 answer:
ryzh [129]3 years ago
6 0

Answer:

Explanation:

a) taking 00000005, it is a 13th bit which is 0, and therefore, we'd call it an ordered chunk

b) taking 00000005 again, it is 14th (B) and 15th (E) bits are 0 and so we'd call it a middle fragment

c) 00000015 is equal to 21, it is not a multiple of 4, and as such, it needs 3 padding bytes

d) 00000005 is equal to 5 making it a TSN. So the TSN is 5

e) taking 0003, we can then say the SI is 3

f) taking 000A, the SSN is then 10

g) the message is 48656C6C

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Answer:

Check the output

Explanation:

# -*- coding: utf-8 -*-

"""

Created on Thu Apr 12 00:39:11 2018

author:

"""

stocks ={

       "tomato soup": 20,

       "cheese": 8,

       "bread": 6,

       "milk": 8,

       "butter": 7,

       "coffee": 8,

       "ice cream": 5,

       "orange juice": 12,

       "bacon": 6,

       "tortilla chips": 14,

       "ramen": 24 }

prices ={

       "tomato soup": 1.85,

       "cheese": 3.99,

       "bread": 2.50,

       "milk": 3.59,

       "butter": 1.99,

       "coffee": 5.99,

       "ice cream": 2.99,

       "orange juice": 2.50,

       "bacon": 5.49,

       "tortilla chips": 3.00,

       "ramen": 0.99 }

def grocery_cost(item_list,quantity_list):

   totalcost = 0

   for i in range(len(item_list)):

       totalcost=totalcost+(quantity_list[i]*prices[item_list[i]])

       

   return totalcost

def stock(item):

   print("Number of itmes present in the stock:",stocks[item])

print("Welcome to the on-line grocery store!!")

print("Items that are available for purchase:")

for key in stocks.keys():

   print(key)

#chosen foods

print("Enter the item with quantity or Enter 'Q' when you are done")

item_list=[]

quantity_list=[]

while True:

   item=input('Enter the item name: ')

   if item=='Q' or item=='q':

       break

   item_list.append(item)

   while True:

       quan=int(input('Enter the number of item: '))

       if stocks[item] >=quan:

           quantity_list.append(quan)

           break

       else:

           stock(item)

           print('Your requirement is higher than stock available. Please enter again!!')

print("\nTotal cost:", "$",grocery_cost(item_list,quantity_list))

Kindly check the output in the attached image below.

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instructor is describing a component that is always located on the CPU and accelerates the processing of instructions. Which com
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Answer:

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Explanation:

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2.<br> Solve each equation.<br> a)<br> 3n - 8 = 2n + 2<br> b)<br> 4n + 75 = 5n + 50
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Answer:

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