Yes, I will list acute first (<90) and obtuse second (>90) and they need to add to 180
10 and 170
20 and 160
30 and 150
40 and 140
50 and 130
60 and 120
70 and 110
80 and 100 and so on
Answer:
t = 7 + 3i
Step-by-step explanation:
(t-7)^2 + 18 = 9
(t-7)^2 = 9 - 18
(t-7)^2 = -9
(t-7) = sqrt(-9) = |3| sqrt(-1)
t = 7 + 3i
Hi,
To solve this problem, Let us take the LCM of 10 and 16 which will come 80.
Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n
According to the question, CP of 10 tables is equal to the SP of 16 tables, then
the SP of 16 tables will also be ₹ n.
So, SP of 80 tables will be ₹ 5n
So, Loss = CP-SP
→ 8n - 5n = ₹ 3n
Loss%= (3n×100)/8n
Loss%= 37.5%.
Hence the correct answer will be a <u>loss of 37.5%.</u>
N= -4
-4/2+5=3
-2+5=3 you have to subtract the 5 from three first and then multiply the answer by 2 to get n
