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3 years ago

What is the slope of the line.

Mathematics

1 answer:

Naily [24]3 years ago

7 0

Answer:

m=3/2 or m=1.5

Step-by-step explanation:

slope formula:

m=(y1-y2)/(x1-x2)

in order to get this we need two points such as (3,0) and (1,-3) which are points on this line. So:

m=(0-(-3))/(3-1)

m=3/2 or m=1.5

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Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
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HYP denote the hypotenuse.

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Sin(M) = OPP/HYP
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using the Pythagorean we can find the length of AB:

$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
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$Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}$
$Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}$
$Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}$
$Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}$
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