Answer:

Step-by-step explanation:

So if it is 3 for $2 you multiply 2 by 4 because 3*4=12 and that is one dozen.
So the answer you are looking for is 2*4=8. So one dozen is $8.
Answer:
The second statement is true.
Step-by-step explanation:
Draw the corresponding parabola and use it to verify all statements.
picture unclear because it is to find the sum of consecutive numbers 1 to 100, you multiply the number of sets (50) by the sum of each set (101): 101(50)=5050.{\displaystyle 101(50)=5050.} So, the sum of consecutive number 1 through 100 is 5,050 .