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inessss [21]
3 years ago
5

Brandon wants to buy a specific baseball bat. He is hoping that he will be able to save enough money to buy it in time for the s

ummer baseball season. The new Super Pro Aluminum Bat costs $179.99 plus 6% sales tax. Brandon has already saved $62.50 from mowing lawns. He will continue his summer job and earn $31.25 per week. How many weeks will it take him to save enough money for the baseball bat?
Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0
179.99x 6%= 10.79      179.99 +10.79=190.78                                                190.78 - 62.50=128.28 dollars that Brandon still needs to buy the baseball hat. 31.25 x 4=125.00 which is not enough. 31.25x5=156.25 so it will take Brandon another 5 weeks to save the rest of the money for the hat.
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Answer:

12

Step-by-step explanation:

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3 years ago
Consider the conditional statement of N is the midpoint of CD then CD =2CN what is the hypothesis
iogann1982 [59]

Answer:

Step-by-step explanation:

If N is the midpoint of CD, it means that N bisects the line CD. Hence;

CN + ND = CD .... 1 and;

CN = ND .... 2

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Rearrange;

CD = 2CN (proved)

The hypothesis is the midpoint hypothesis and the hypothesis is TRUE

5 0
3 years ago
Simplify the given expression below:
Zina [86]
The answer will be C. OR 3. 11−<span>13<span>i</span></span>
4 0
4 years ago
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The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If
frutty [35]
For this case we have the following equation:
 w = 0.9* \sqrt{E}
 Where,
 w: The weight of a spring in pounds
 E: the energy stored by the spring in joules.
 Substituting values we have:
 w = 0.9* \sqrt{12}
 Making the corresponding calculation:
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4 0
3 years ago
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Which equation has x = -i and x = = 21v3 as two of its solutions?
Drupady [299]

Answer:

The equation in option A is correct.

Step-by-step explanation:

Given the equation

\:y=x^4+13x^2+12

Let us find the solution by setting y=0

x^4+13x^2+12=0\:\:\:\:\:

\mathrm{Rewrite\:the\:equation\:with\:}u=x^2\mathrm{\:and\:}u^2=x^4

u^2+13u+12=0

if ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

u+1=0\quad \mathrm{or}\quad \:u+12=0

u=-1,\:u=-12

\mathrm{Substitute\:back}\:u=x^2,\:\mathrm{solve\:for}\:x

x^2=-1,\:x^2=-12

solving

x^2=-1

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{-1},\:x=-\sqrt{-1}

x=i,\:x=-i            ∵ \:\sqrt{-1}=i

solving

x^2=-12

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{-12},\:x=-\sqrt{-12}

x=2\sqrt{3}i,\:x=-2\sqrt{3}i

Hence, the solutions are:

x=i,\:x=-i,\:x=2\sqrt{3}i,\:x=-2\sqrt{3}i

Therefore, the equation in option A is correct.

6 0
3 years ago
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