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seropon [69]
3 years ago
10

Simplify 4radical2plus7radical2minus3radical2

Mathematics
1 answer:
zlopas [31]3 years ago
3 0
Let "radical 2" be represented by "r."

Then you are to simplify 4r + 7r - 3r.  This comes out to 11r - 3r = 8r.

The answer is 8 radical 2.


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In the figure, lines a, b, and c are parallel and m∠4=68° . Drag and drop the correct angle measure for each angle. m∠1 = m∠2 =
melisa1 [442]
The complete question in the attached figure

we have that
<span>m∠4=68°

we know that
</span>m∠4 and m∠3 are supplementary angles
so
m∠3=180-m∠4----- m∠3=180-68------> m∠3=112°

m∠3 = m∠2 --------> by alternate interior angles
so
m∠2=112°

m∠1 = m∠4 --------> by alternate exterior angles
so
m∠1=68°

m∠5 = m∠4---------> by corresponding angles
so
m∠5=68°

the answers are
m∠1=68°
m∠2=112
m∠3=112°
m∠5=68°



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Answer:

Step-by-step explanation:

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If (angle)1 = 7x and (angle)4 = 3x + 20, what is the value of x?
Semenov [28]
The value of x is 5. Angle one and four are vertical. You can do this by writing 7x = 3x + 20. Isolate the variable by moving 3x to the other side. If you do this, 3x becomes negative, and you end up with 7x-3x = 20 --> 4x = 20.
x=5.
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A pan of warm water (46∘ Celsius) was put in a refrigerator. After 15 minutes, the water's temperature was 27∘ C; 15 minutes aft
Cloud [144]

Answer:

The refrigerator was at around 13 ∘C

Step-by-step explanation:

Newton's Law of Cooling:

The rate of change of a body temperature  (amount of heat loss/time of loss) is directly proportional to the difference between its own temperature and the surroundings.

\frac{T(t2)-T(t1)}{t2-t1} = -h (T(t2) - Tenv)

T ⇒ temperature

t ⇒ time

Tenv ⇒refrigerator temperature

\frac{T(t2)-T(t1)}{t2-t1} ⇒ rate of change of he temperature

-h ⇒ constant of proportionality (negative because the temperature is decreasing inside the refrigerator)

We have 3 points:

time (minutes) - Temperature (∘ C)

0 (when the pan was put in the refrigerator) - 46

15 (after 15 minutes) - 27

30 (15 minutes after the first 15 minutes) - 19

\frac{27 - 46}{15 - 0} = -h (27 - Tenv)

\frac{19 - 27}{15 - 0} = -h (19 - Tenv)

Now we have a system of two equations and two variables

\frac{-19}{15} = -h (27 - Tenv)\\ \frac{19}{15} = h (27 - Tenv)\\ \frac{19}{15(27 - Tenv)} = h

\frac{19 - 27}{15 - 0} = -h (19 - Tenv)\\\frac{-8}{15} = -h (19 - Tenv)\\\frac{8}{15} = h (19 - Tenv)\\\frac{8}{15} = \frac{19}{15(27 - Tenv)} (19 - Tenv)\\8(27 - Tenv) = 19 (19 - Tenv)\\216 - 8 Tenv = 361 - 19 Tenv\\19 Tenv - 8 Tenv = 361 - 216\\11 Tenv = 145 \\Tenv = 145/ 11\\Tenv = 13. 18

The refrigerator was at around 13 ∘C

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3 years ago
What type of triangle is shown? (3 points)
const2013 [10]

Answer:

B. isosceles triangle

Step-by-step explanation:

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3 years ago
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