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Dominik [7]
3 years ago
14

Chau made $252 for 18 hours of work.

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

$126.00

Step-by-step explanation:

divde by 2

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A circle is centered at (3,8) and is tangent to the x-axis. write its equation in standard form.
Tema [17]

Answer:

hi

Step-by-step explanation:

8 0
3 years ago
If there are 5 terms in a quadratic sequence
exis [7]

Answer:

7.2

Step-by-step explanation:

First differences:

0.8-0.2, 1.8-0.8, 3.2-1.8, 5.0-3.2

0.6, 1.0, 1.4, 1.8

Second differences:

1.0-0.6, 1.4-1.0, 1.8-1.4

0.4, 0.4, 0.4

For the next term, add 0.4 to the last term from the first differences, and add the sum to the last term of the quadratic sequence:

0.4+1.8=2.2

2.2+5.0=7.2

∴ The next term in the sequence is 7.2

7 0
3 years ago
Solve for y in terms of x <br><br> -8x + 4y = -16
solniwko [45]

Answer:

y=2x-4

Step-by-step explanation:

well first you have to move the -8x to the other side where the -16 is. by doing so, the -8x will turn into a POSTIVE 8x. than your problem should look like (4y=8x-16). now that your problem is like that, you want "y" to be alone. so, you divide the 4 by every number. (so you would do 4y/4, 8x/4, and -16/4). than your final product would be: y=2x-4

4 0
3 years ago
Read 2 more answers
8 - 2x = 5(x - 2) which step is not part of solving the problem?
RUDIKE [14]
C. 8 - 2x = 5x - 2         is the anwser
7 0
3 years ago
Read 2 more answers
you pick a card at random without getting the first card back you pick a second card at random what is the probability of pickin
Keith_Richards [23]

We have to calculate the probability of picking a 4 and then a 5 without replacement.

We can express this as the product of the probabilities of two events:

• The probability of picking a 4

,

• The probability of picking a 5, given that a 4 has been retired from the deck.

We have one card in the deck out of fouor cards that is a "4".

Then, the probability of picking a "4" will be:

P(4)=\frac{1}{4}

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

P(5|4)=\frac{1}{3}

We then calculate the probabilities of this two events happening in sequence as:

\begin{gathered} P(4,5)=P(4)\cdot P(5|4) \\ P(4,5)=\frac{1}{4}\cdot\frac{1}{3}=\frac{1}{12} \end{gathered}

Answer: 1/12

8 0
1 year ago
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