-3x - 42 > 3 |+42
-3x > 45 |change the signs
3x < -45 |:3
x < -15 → x ∈ (-∞, -15)
Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F =
where k=

So , 2.2 =
(
So , q ² = (
)
For charge magnitude
I.e q ² = 
so, q = 
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer
Answer:
(3/26, 38/13)
Step-by-step explanation:
I hope I solved it right and it helped you somehow
If you have any questions about the way I solved it, don't hesitate to ask :)
3. Sqrt of 40
4. Sqrt of 148
Distance formula is sqrt of (x-x1)^2+(y-y1)^2
So (-4-2)^2+ (3-5)^2
(-6)^2+(-2)^2
36+4
Sqrt of 40
Do the same process for 4!
Ps don’t forget to keep the square root
Answer:
the answer is D
Step-by-step explanation: