u₁₂ represents the amount of loan remaining after 12 years
<h3>How to interpret u₁₂?</h3>
The function is given as:
u₀ = 8000
Given that the subscript n in 
represents number of years and represents the amount left to be paid after n years.
We can conclude that:
u₁₂ represents the amount of loan remaining after 12 years
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Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
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Follow the order of operations. Evaluate absolute value first.
-3^2+8/2*4-9
Then evaluate exponents
9+8/2*4-9
Then evaluate multiplication and division from left to right
9+4*4-9
9+16-9
Then evaluate addition and subtraction from left to right
25-9
16
Final answer: 16
Answer:
94 boys and 56 girls.
Step-by-step explanation:
150/8 = 18.75 = x
b=x*5 = 94
g=x*3 = 56
b+g=150
