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Tema [17]
3 years ago
7

How many milliliters of a 12-molar HCl must be diluted to obtain 2.0 liters of 3.0-molar HCl?

Chemistry
1 answer:
Vladimir [108]3 years ago
7 0

Answer: 500ml

Explanation:

Using the Dilution formula that

C₁V₁=C₂V₂

Where

C₁=the molarity of  concentrated solution

= 12 M

V₁ = Volume of the concentrated solution

=?

C₂=the molarity of  the diluted solution

=3.0M

V₂= Volume of the diluted  solution= 2 liters

Changing 2 liters to millilitres  

1000ml= 1 Liters

2Liters=2000ml

Bringing the formulae and inputting the given values

C₁V₁=C₂V₂

12 x V₁= 3.0 x 2000ml

V₁= 3.0 x 2000 / 12

V₁=500ml

Therefore 500ml of 12-molar HCl mst be diluted to obtain 2 Liters of 3.0 Molar HCl.

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Compute the number of grams(g) of lead in 22.5 moles of lead.
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Explanation:

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A Mercury(II) chloride dissolves in water to give poorly conducting solutions, indicating that the compound is largely nonionize
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Using valence bond theory, HgCl2 is sp hybridized while PCl3 is sp3 hybridized.

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Who is the father of chemistry ​
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3 years ago
How many grams of potassium chlorate must be heated to produce 30.0g of oxygen? socratic.org
DanielleElmas [232]

Answer:

76.56g

Explanation:

Firstly, to do this we need a correct and balanced equation for the decomposition of potassium chlorate.

2KClO3 —-> 2KCl + 3O2

From the balanced equation, we can see that 2 moles of potassium chlorate yielded 3 moles of oxygen gas

We need to know the actual number of moles of oxygen gas produced. To do this, we divide the mass of the oxygen gas by its molar mass. Its molar mass is 32g/mol

The number of moles is thus 30/32 = 0.9375 moles

Now we can calculate the number of moles of potassium chlorate decomposed.

We simply do this by (0.9375 * 2)/3 = 0.625 moles

Now to get the number of grammes of potassium chlorate decomposed, we simply multiply this number of moles by the molecular mass. The molecular mass of KClO3 is 39 + 35.5 + 3(16) = 122.5g/mol

The amount in grammes is thus 122.5 * 0.625 = 76.56g

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