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lesya [120]
3 years ago
7

Compute the number of grams(g) of lead in 22.5 moles of lead.

Chemistry
1 answer:
iogann1982 [59]3 years ago
7 0

Answer:

4662 in grams

Explanation:

hope this helps :).

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25. In a titration 17ml of 0.2M NaOH was used to neutralize 10ml of acetic acid (CH3 COOH) What is the molarity of the acetic ac
melisa1 [442]
The  molarity  of  acetic  acid  is  calculated  as  follows

find  the  number  of moles  of NaOH  =  molarity  x  volume
=   17x0.2  =   3.4  moles


write  the  equation  for  reaction
  CH3COOH  +  NaOH  =  CH3COONa  +H2O

since  ratio  is be  of  CH3COOH  to  NaOH  is   1:1  the  moles  of CH3COOH   is  therefore =  3.4  moles

therefore  the  molarity  = moles/volume
=  3.4  /10  =  0.34 M
6 0
4 years ago
Which type of bond will most likely be found in HBr?
NARA [144]
<span>HBr is covalent bond.!

</span>Hydrogen and Bromine will share their electrons, to obtain the electron configuration of a noble gas<span>.
</span>
hope this helps!

6 0
3 years ago
Read 2 more answers
question if the following elements were involved in a chemical reaction, which one would be most likely to form a cation? respon
Serjik [45]

Fluorine (F) would be least likely to form a cation out of potassium, fluorine, chlorine, and nitrogen.

  • A cation is a positively charged atom (or molecule) that has lost electrons (or electrons).
  • The tendency for electropositive elements to lose electrons and produce cations is greater. On the left side of the periodic table, these are often metals.
  • Going down a group increases electropositivity, or the propensity to lose electrons and generate cations. and decreases across a period. In the given examples:
  • Potassium, K is an alkali metal and will lose electrons readily to form a cation.
  • Nitrogen (N), Fluorine (F), and chlorine (Cl) are all nonmetals that prefer to accept electrons and form anions instead. F is the most electronegative i.e. it will gain electrons and form F- rather than F+.

To learn more about cation visit:

brainly.com/question/28710898

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5 0
1 year ago
6.
levacccp [35]

Answer:

the time required for one half of a sample of a radioisotope to decay

7 0
2 years ago
How many grams of air are required to complete the combustion of 120 g of phosphorous to diphosphorous pentoxide, assuming the a
DiKsa [7]

Answer:

Explanation:

522 g

Explanation:

Your starting point here will be the balanced chemical equation for this combustion reaction

4

P

(s]

+

5

O

2(g]

→

2

P

2

O

5(s]

Notice that you have a

4

:

5

mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need

5

4

time more moles of oxygen gas.

Use phosphorus' molar mass to determine how many moles you have in that

93.0-g

sample

93.0

g

⋅

1mole P

30.974

g

=

3.0025 moles P

Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction

3.0025

moles P

⋅

5

moles O

2

4

moles P

=

3.753 moles O

2

7 0
3 years ago
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