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mrs_skeptik [129]
3 years ago
10

A spherical balloon is inflated so that its radius increases at a rate of 2 cm/sec. How fast is the volume of the balloon increa

sing when the radius is 3 cm
Mathematics
1 answer:
Nataly [62]3 years ago
7 0

Answer:

72πcm³/s

Step-by-step explanation:

Volume of the spherical balloon V = 4/3πr³

dV/dr = 4πr²

The rate at which the volume of the balloon increasing is expressed as;

dV/dt = dV/dr • dr/dt

dV/dt = 4πr² • (2)

Given

Radius r = 3cm

dV/dt = 4π(3)² • (2)

dV/dt = 36π×2

dV/dt = 72πcm³/s

Hence the rate at which the volume is increasing is 72πcm³/s

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The sum of two numbers is 54.The smaller number is 22 less than the larger number.what are the numbers?
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=> 12^3 x 11^3
If we solve this equation following the rule of exponent will get the correct answer:
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