Find midpoint of line segment joining j(6 17 and i(9 16)
1 answer:
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Answer:
solution given;
let
AB=a
AC=b=30ft
AB=c=20ft
<A=115°
By using Cosine rule.
a²=b²+c²-2bc cos angle
a²=30²+20²-2*30*20 Cos 115°
a²=1807.1419
a=√[1807.1419]
a=42.51
Side A is 42.51ft.
Again
Cos B=
Cos B=
Cos B=0.7687
<B=Cos -¹(0.7687)
<B=39.46°
Angle B is 39.46
Answer:
Step-by-step explanation:
See attachment for complete question.
From the attachment, there are 3 columns and 3 rows
The 3 columns represent the first factor
To get the second factor, we have to analyze the 3 rows in the attachment.
Notice that the first row is bigger than the other two rows.
This big row will be represented with variable x
Notice that the boxes in second row are smaller than the first row and the + sign is written on each of the boxes.
This is represented with + 1
Also, notice that the boxes in third row are smaller than the first row and the + sign is written on each of the boxes.
This is also represented with + 1
Hence, the expression for the rows is x + 1 + 1 = x + 2
The product is then calculated as:
