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liq [111]
3 years ago
11

3/5n+15=10+2/5n what is n

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

\textsf{Hey there!}

\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}

\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}

\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}

\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}

\textsf{Solve\ the set we have left over}

\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}

\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}

\mathsf{\dfrac{1}{5}n+15-15=10-15}

\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }

\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }

\mathsf{10-15=-5}

\mathsf{New\ equation: \dfrac{1}{5}n=-5}

\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}

\mathsf{\dfrac{1}{5}n\times5=5\times-5}

\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \  it \ gives \ us \ 1}\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}

\mathsf{n =5\times-5}\\\mathsf{5\times-5 = -25}

\textsf{Thus, \underline{\bf{n = -25}}}\checkmark

\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\bf{n =-25}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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Chevy has some yarn that he wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each sc
Rashid [163]

Answer:

The system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.

Step-by-step explanation:

Let number of hat Chevy makes be h.

Also Let number of scarves Chevy makes be s.

Given:

Total Amount of yarns = 2 kg

Total number of items = 15

Since Items need to make are hat and scarves.

Hence the equation can be represented as;

h+s=15 \ \ \ \ equation \ 1

Again Given:

Each hat uses 0.2 kilograms of yarn.

each scarf uses 0.1 kilograms of yarn.

Hence the equation can be represented as;

0.2h+0.1s=2 \ \ \ \ \ equation \ 2

Hence the system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Now Solving these to find number of hats and number of scarves.

Multiplying equation 2 with 10 we get;

10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3

Now Subtracting equation 1 from equation 3 we get;

(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5

Now Substituting the value of h in equation 1 we get;

h+s= 15\\5+s =15\\s=15-5\\s=10

Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.

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Single interest uses an arithmetic formula where as compound interest uses a geometric formula
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Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)
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Answer:

f_x(x,y,z)=4\sin (y-z)

f_x(x,y,z)=4x\cos (y-z)

f_z(x,y,z)=-4x\cos (y-z)

Step-by-step explanation:

The given function is

f(x,y,z)=4x\sin (y-z)

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

f_x(x,y,z)=4(1)\sin (y-z)

f_x(x,y,z)=4\sin (y-z)

Differentiate partially w.r.t. y and x, z are constants.

f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)

f_y(x,y,z)=4x\cos (y-z)

Differentiate partially w.r.t. z and x, y are constants.

f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)

f_z(x,y,z)=4x\cos (y-z)(-1)

f_z(x,y,z)=-4x\cos (y-z)

Therefore, the first partial derivatives of the function are f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z).

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Answer:

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Hope this helps! Have an amazing day!

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