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DIA [1.3K]
3 years ago
7

What expression is equivalent to 2 m plus m plus m

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0

Answer: 2m+m+m is really the same thing as saying m+m+m+m, or 4m. Use whatever you like as the expression :)

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A triangle has an area of 9m2 and a base of 6m. how do I find the height of this triangle?
KonstantinChe [14]
You know the triangle has a base of 6 meters, and that the formula to find the area of a triangle is 1/2bh or one-half of the base times the height. So, you would plug in 9 meters squared=one half of six times h, or 9m^2=1/2(6)*(h). In simplifying this, you would get 3h=9m^2. Divide both sides by three and get h=3. Hope this helps, and if you need any further explanations, please let me know!
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3 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

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Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

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A reflection over the y-axis :)

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