We need the half-life of C-14 which is 5,730 years.
Now, we will need a half-life equation:
elapsed time = half-life * log (bgng amt / ending amt) / log 2
We'll say beginning amount = 100 and ending amount = 41
elapsed time = 5,730 * log (100/41) / log 2
elapsed time = 5,730 * log (
<span>
<span>
<span>
2.4390243902
</span>
</span>
</span>
) / 0.30102999566
elapsed time = 5,730 * 0.38721614327 / 0.30102999566
elapsed time =
<span>
<span>
</span></span><span><span><span>5,730 * 1.2863041851
</span>
</span>
</span>
<span>elapsed time = 7,370.523 years
Source:
http://www.1728.org/halflife.htm </span>
Basically, ur just solving for y
6x + 4y = 8...subtract 6x from both sides
4y = -6x + 8....now divide both sides by 4
y = (-6/4)x + 8/4...reduce
y = -3/2x + 2 <=== slope intercept form
Act like the two triangles are one and to find z and find the others find z first comment if you didn’t understand and I will go into it with more detail
If we multiply and then divide the number by the same thing,
we won't change its value.
Take the number: 58,000,000,000
Divide it by 10¹⁰ : 5.8
Multiply it by 10¹⁰ : 5.8 x 10¹⁰
They want a single digit, so we'll round the 5.8
to the nearest whole number:
6 x 10¹⁰ .
