Quadrilateral FLAG has coordinates F(1,5), L(6,3), A(3,-1), and G(-2,1). Which
2 answers:
Answer:
- B. Quadrilateral FLAG is a parallelogram because opposite sides are parallel.
Step-by-step explanation:
<em>Refer to attached.</em>
Plot the point and connect in order FLAG.
<u>We see </u>
- FL ║ GA
- GF ║ AL
- FA and GL are not perpendicular
<u>All the above can be confirmed by calculating the slopes:</u>
- m(FL) = (3 - 5)/(6 - 1) = -2/5
- m(GA) = (1 + 1)/(-2-3) = -2/5
- These are same.
- m(GF) = (5 - 1)/(1 + 2) = 4/3
- m(AL) = (3 + 1)/(6 - 3) = 4/3
- These are same
- m(FA) = (-1 - 5)/(3 - 1) = -3
- m(GL) = (3 - 1)/(6 +2) = -1/4
- These are negative but not reciprocal
The quadrilateral is a parallelogram.
Correct choice is B
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Answer:
36.72
Step-by-step explanation:
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Answer:
A) see attached for a graph. Range: (-∞, 7]
B) asymptotes: x = 1, y = -2, y = -1
C) (x → -∞, y → -2), (x → ∞, y → -1)
Step-by-step explanation:
<h3>Part A</h3>A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:
This has a vertical asymptote at x=1, and a hole at x=2.
The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.
The graph is attached.
The range of the function is (-∞, 7].
__
<h3>Part B</h3>As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.
The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.
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<h3>Part C</h3>The end behavior is defined by the horizontal asymptotes:
for x → -∞, y → -2
for x → ∞, y → -1
