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makkiz [27]
3 years ago
13

PLEASE HELP URGENT!!!!!!!! NUMBER 46 AND 47!!!!!!!!!!!!!!

Mathematics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

46 is d I'm not sure for 47 but I think it's c not sure tho

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The function f(x) = 1/3x + 5 and g(x) = x^2 + 4x are shown graphed below. The negative solution to the equation f(x) = g(x) is c
sergij07 [2.7K]

Answer:

Step-by-step explanation:

4 0
2 years ago
Use the system of equations and graphs below to complete the sentence. x − 2 ⁢ y = 5 3 ⁢ x + 15 ⁢ y = − 6 Set of 4 graphs are re
Leno4ka [110]

The solution to the given system of linear equations is (3, -1)

<h3>Graph of Linear Equations</h3>

From the question, we are to determine the graph of the system of linear equations

The given system of equations is

x - 2y = 5

3x + 15y = -6

The graph of the given system of equation is shown below

From the graph,

The point of intersection of the lines is at (3, -1)

Hence, the solution to the given system of linear equations is (3, -1)

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1 year ago
Jordan is picking berries. The number of blueberries he
inna [77]
D. x/3 - 5
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4 0
2 years ago
Write the equation of the line that passes through (-6,0) and is parallel to the line y=5x-43
AVprozaik [17]

The equation of the line that passes through (-6,0) and is parallel to the line y = 5x - 43 in slope intercept is y = 5x + 30

<em><u>Solution:</u></em>

Given that line that passes through (-6, 0) and is parallel to the line y = 5x - 43

We have to find the equation of line

Let us first find slope of line having equation y = 5x - 43

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c  ------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing equation of line y = 5x - 43 with slope intercept form y = mx + c,

we get m = 5

Thus slope of given line is 5

We know that slopes of parallel lines are equal

Thus the slope of line parallel to given line is also 5

Now let us find equation of line having slope "5" and passes through (-6, 0)

Substitute m = 5 and (x, y) = (-6, 0) in eqn 1

y = mx + c

0 = 5(-6) + c

<h3>c = 30</h3>

<em><u>Thus the required equation is:</u></em>

Substitute c = 30 and m = 5 in eqn 1

y = 5x + 30

Thus the required equation of line is found

8 0
2 years ago
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