PLEASE HELP URGENT!!!!!!!! NUMBER 46 AND 47!!!!!!!!!!!!!!
1 answer:
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Answer:
Step-by-step explanation:
This is a conditional probability exercise.
Let's name the events :
I : ''A person is infected''
NI : ''A person is not infected''
PT : ''The test is positive''
NT : ''The test is negative''
The conditional probability equation is :
Given two events A and B :
P(A/B) = P(A ∩ B) / P(B)
P(A/B) is the probability of the event A given that the event B happened
P(A ∩ B) is the probability of the event (A ∩ B)
(A ∩ B) is the event where A and B happened at the same time
In the exercise :
We are looking for P(I/PT) :
P(I/PT)=P(I∩ PT)/ P(PT)
P(PT/I)=P(PT∩ I)/P(I)
0.904=P(PT∩ I)/0.025
P(PT∩ I)=0.904 x 0.025
P(PT∩ I) = 0.0226
P(PT/NI)=0.041
P(PT/NI)=P(PT∩ NI)/P(NI)
0.041=P(PT∩ NI)/0.975
P(PT∩ NI) = 0.041 x 0.975
P(PT∩ NI) = 0.039975
P(PT) = P(PT∩ I)+P(PT∩ NI)
P(PT)= 0.0226 + 0.039975
P(PT) = 0.062575
P(I/PT) = P(PT∩I)/P(PT)
Answer:
y = 1/2x + 4
Step-by-step explanation:
Use the formula for the equation of a line.
y = mx + b
Where m is the slope, and b is the y-intercept.
The slope is given.
y = 1/2x + b
The points (x, y) are given.
(4, 6)
Put y as 6 and x as 4, solve for b.
6 = 1/2(4) + b
6 = 2 + b
6 - 2 = b
4 = b
The y-intercept is 4 or (0, 4).
The equation of the line is y = 1/2x + 4.
