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makkiz [27]
3 years ago
13

PLEASE HELP URGENT!!!!!!!! NUMBER 46 AND 47!!!!!!!!!!!!!!

Mathematics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

46 is d I'm not sure for 47 but I think it's c not sure tho

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What is 9% of 42 pls help fast!
joja [24]

Answer:

3.78

Step-by-step explanation:

Percentage solution with steps:

Step 1: We make the assumption that 9 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=9$.

Step 4: In the same vein, $x\%=42$.

Step 5: This gives us a pair of simple equations:

$100\%=9(1)$.

$x\%=42(2)$.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{9}{42}$

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{42}{9}$

$\Rightarrow x=466.67\%$

Therefore, $42$ is $466.67\%$ of $9$.

4 0
3 years ago
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Which equation represents the circle described?
bazaltina [42]

We have the equation:

x^2+y^2-8x-6y+24=0


By arranging this equation in terms of x and y, we have:


x^2-8x+y^2-6y=-24 \\ \\


By using the method of completing the square, we have:

x^2-8x+\mathbf{\left(\frac{8}{2}\right)^2}+y^2-6y+\mathbf{\left(\frac{6}{2}\right)^2}=-24+\mathbf{\left(\frac{8}{2}\right)^2}+\mathbf{\left(\frac{6}{2}\right)^2} \\ \\ x^2-8x+\mathbf{16}+y^2-6y+\mathbf{9}=-24+\mathbf{16}+\mathbf{9} \\ \\ \boxed{(x-4)^2+(x-3)^2=1}


The center of this circle is:

(h,k)=(4,3)


So the equation that fulfills the statement is:

(x-4)^2+(y-3)^2=2^2


Finally, the right answer is c)

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3 years ago
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What is 481 divided by 8?Is it 60 with a remainder of 1 ?
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Yes. 60 remain 1 or 60.125 . 
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Kelly rides her bicycle from city a to city b how long is her ride ? A 70 miles B 24 miles
KATRIN_1 [288]
I think it is B (don't take me for certain cuz I don't know)
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3 years ago
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Faces A and C are squares.
zysi [14]
Answer

Square prism

It has 2 squares and 4 rectangles
4 0
3 years ago
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