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drek231 [11]
3 years ago
5

What is the best classification of 0 in the real number system?

Mathematics
1 answer:
lesantik [10]3 years ago
3 0

Answer:

Step-by-step explanation:

The 0 in the real number system goes into the most specific subset of real numbers we have, which is the whole numbers.  Whole numbers include the 0, and next is the less specific natural or counting numbers which do not include the 0. (Next comes the integers and after that rational numbers, each getting less specific as they radiate out from the center)

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2x+7 =5 is an example of...
tresset_1 [31]

Answer:

This is an example of distribution

Step-by-step explanation:

The reason why is because the equation is linear and if you exclud the y it show that it can distribute.

6 0
3 years ago
HELP I NEED HELP ASAP
pentagon [3]

Answer:

Answer

Step-by-step explanation:

The answer is d because if you at 17 to 197 you'll get 203

6 0
2 years ago
Int(1 \(1 + {e}^{x} )​
Andreyy89

Answer:

\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx}= x - \ln(1 + e^{x}) + C\end{aligned}.

Step-by-step explanation:

The first derivative of the denominator 1 + e^{x} is e^{x}. Rewrite the fraction to obtain that expression on the numerator.

\begin{aligned}\frac{1}{1 + e^{x}} &= \frac{1 + e^{x}}{1 + e^{x}} - \frac{e^{x}}{1+e^{x}}\\&=1-\frac{e^{x}}{1+e^{x}}\end{aligned}.

In other words,

\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\end{aligned}.

Apply u-substitution on the integral \displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx}:

Let u = 1 + e^{x}. u > 1.

du = e^{x}\cdot dx.

\displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx} = \int{\frac{du}{u}} = \ln{|u|} = \ln{u} +C = \ln{(1+e^{x})}+C.

Therefore

\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\\ & = x - \ln{(1 + e^{x})}+C\end{aligned}.

7 0
3 years ago
An environmental agency worries that many cars may be violating clean air emissions standards. The agency hopes to check a sampl
goldenfox [79]

Answer:

197

Step-by-step explanation:

Sample proportion is; p^ = 12/50 = 0.24

Margin of error of 5% is given by the formula;

ME = (z_0.05) √[p^(1 - p^)/n]

Let's make n(number of sample) the subject.

n = ((z_0.05)/ME)²((p^)(1 - p^))

From tables, the z-score of 0.05 is 1.645

Thus;

n = ((1.645)/0.05)²(0.24(1 - 0.24))

n ≈ 197

3 0
3 years ago
2. The volume of gas in a container at a constant temperature varies inversely as the pressure.
MrMuchimi

\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{\textit{\boxed{v}olume varies inverse as the \boxed{p}ressure}}{v = \cfrac{k}{p}}\qquad \textit{we also know that} \begin{cases} v = \stackrel{cm^3}{26}\\ p=\stackrel{lbs}{6} \end{cases} \\\\\\ 26=\cfrac{k}{6}\implies 156=k~\hfill \underset{\textit{part a)}}{\boxed{v = \cfrac{156}{p}}} \\\\\\ \textit{when p = 17, what is "v"?}\qquad v = \cfrac{156}{17}\implies v = 9\frac{3}{17}\implies \underset{\textit{part b)}}{v\approx 9.18~cm^3}

3 0
3 years ago
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