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2 years ago

Can you guys help i’m kinda struggling

Mathematics

1 answer:

professor190 [17]2 years ago

6 0

Answer:

D. GH = MN

Step-by-step explanation:

Second side is needed to prove congruence by SAS

Side must be on opposite side of equal angles given

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(x - 1)(x + 5) = x² + 4x – 2<br><br> Step by step if possible please

anastassius [24]

Answer:

solve or simplify? if solve, what is x

Step-by-step explanation:

5 0

2 years ago

What is the solution to the equation x + 14 = 63? (Input a whole number only.) (3 points) Blank 1:

Alex

Hey there!

This is a one-step equation, meaning that we can solve it in one step.

This is the step:

Subtract 14 from both sides

Goal:

To find out the value of x

Subtract 14:

x+14-14=63-14

the 14's on the left cancel:

x=49

Hence, the answer is

$\boxed{\boxed{\bold{x=49}}}$

Hope everything is clear.

Let me know if you have any questions!

#LearningDoesn'tEnd

:-)

$\rule{200}{2}$

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2 years ago

What's the answer please, I need help

mezya [45]

Answer:

Ano pong sa Sagutin diyan

Step-by-step explanation:

hindi ko op maintiddihan sorry po

3 0

2 years ago

Mr. Daniels is organizing a class trip on a budget of $900. The bus rental costs $600. Mr. Daniels will also buy tickets that co

Mars2501 [29]

Answer:

Mr.Daniels is a fajjett

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Remember to show work and explain. Use the math font.

MrMuchimi

Answer:

$\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}$

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================$

$1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}$

$\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)$

$--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)$

$--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}$

6 0

3 years ago