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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Csqrt%7B49%20%5Ctimes%207%7D%20%7D%20" id="TexFormula1" title=" \sqrt{ \sqrt

yuradex [85]

$\sqrt{ \sqrt{49 \times 7} } \\ = \sqrt{7 \sqrt{7} } \\ = {7}^{ \frac{1}{2} } \times \sqrt{ {7}^{ \frac{1}{2} } } \\ = {7}^{ \frac{1}{2} } \times {7}^{ \frac{1}{4} } \\ = {7}^{ \frac{3}{4} }$

7 0

3 years ago

Read 2 more answers

Two thirds of a number decreased by six is two. what is the number?

Kisachek [45]

Answer: The number is: " 12 ".

____________________________________
Let "x" represent "the unknown number" (for which we wish to solve.

The expression:

$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;
_______________________________________________
Method 1)

Add "6" to EACH SIDE of the equation;
_______________________________________________
→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:

→ $\frac{2}{3}$ x = 8 ;
______________________________________________
Multiply each side of the equation by " $\frac{3}{2}$ " ; to isolate "x" on one side of the equation ; and to solve for "x" ;
______________________________________________
→ $\frac{3}{2}$ * $\frac{2}{3}$ x = 8 * $\frac{3}{2}$ ;

→ x = 8 * $\frac{3}{2}$ ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;

= $\frac{8*3}{1*2}$ ;

= $\frac{24}{2}$ ;

= 12 .
______________________________________________
x = 12 .
______________________________________________
Method 2)
______________________________________________
$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;

Add "6" to EACH SIDE of the equation;
_______________________________________________
→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:
→ $\frac{2}{3}$ x = 8 ;
______________________________________________
Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
 → 3 * $\frac{2}{3}$ x = 8 * 3 ;
→ $\frac{3}{1}$ * $\frac{2}{3}$ x = 8 * 3 ;
→ $\frac{3*2}{1*3}$ x = 8 * 3
→ $\frac{6}{3}$ x = 24 ;

→ 2x = 24 ;

→ Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" :

2x / 2 = 24 / 2 ;

x = 12 .
__________________________________________________
Method 3).
__________________________________________________
$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;
_______________________________________________
Add "6" to EACH SIDE of the equation;
_______________________________________________
→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:

→ $\frac{2}{3}$ x = 8 ;
______________________________________________
Now, divide each side of the equation by " $\frac{2}{3}$ " ;
to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________
{ $\frac{2}{3}$ x } / { $\frac{2}{3}$ } = 8 / { $\frac{2}{3}$ } ;

to get: x = 8 / { $\frac{2}{3}$ } ;

= 8 * ( $\frac{3}{2}$ ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;

= $\frac{8*3}{1*2}$ ;

= $\frac{24}{2}$ ;

= 12 ;
___________________________________________
x = 12 .
___________________________________________
NOTE: Variant: (in "Methods 2 & 3") :
___________________________________________
At the point where:
___________________________________________
= 8 * ( $\frac{3}{2}$ ) ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;
__________________________________________
We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________
{since: "8÷2 = 4" ; and since: "2÷2 =1" } ;
__________________________________________
and we can rewrite the expression:
__________________________________________
$\frac{8}{1}$ * $\frac{3}{2}$ ;
__________________________________________
as: $\frac{4}{1}$ * $\frac{3}{1}$ ;
__________________________________________
which equals:
__________________________________________
→ $\frac{4*3}{1*1}$ ;

= $\frac{12}{1}$ ;

= 12 .
__________________________________________
x = 12 .
__________________________________________
Answer: The number is: " 12 ".
__________________________________________

8 0

4 years ago

Solve the following exponential function 4^3x = 4^2

Alekssandra [29.7K]

For this case we must solve the following equation:

$4^{3x} = 4 ^ 2$

By definition, for the bases to be equal then the exponents must also be the same. Thus, we have to:

$3x = 2$

Dividing by 3 to both sides of the equation we have:

$x = \frac {2} {3}$

Answer:

$x = \frac {2} {3}$

8 0

3 years ago

9. Write an equation parallel to y = 2x + 4that passes through the point (-4,-1).

sasho [114]

Answer:y=2x+7

Step-by-step explanation:

so for the new equation, we know the slope is going to be the same (because its parallel) so for starters we have y=2x+b so now in order to find b (the y-intercept) we have to plug the point into the equation. So it would look like -1=2(-4)+b and then you solve for b and get 7 for b. SO the final answer is y=2x+7.

6 0

3 years ago

5a+3-4a²+2a³ sandard form

tester [92]

2a^3-4a^2+5a+3

Explanation:

For standard form you always start with the one that has the biggest exponent to the least one

4 0

3 years ago