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3 years ago

15

Triangle ABC has virtuces (-2,1),(1,7) and (-2,1) find the vertices of abc the image of abc under the translation that shift the

origin to the point (5,-1)

1 answer:

Mkey [24]3 years ago

3 0

5,-1 is your answer right answer

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5(x-4)=15<br> find out what x is

Digiron [165]

Answer:

7

Step-by-step explanation:

7-4=3

5×3=15

plz mark brainliest

4 0

3 years ago

Read 2 more answers

Need help 25 points

Zina [86]

Answer:

The answer is 50.27 yards.

Step-by-step explanation:

You divide the diameter in 2, which gives you the radius of 4. Then you must square the radius, or multiply it twice, 4 times 4, to get 16. Then multiply that by pi or 3.14, which is 50.27. Hope this helped and please give brainliest if possible! :)

3 0

3 years ago

What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16

blsea [12.9K]

Answer:

<h2>y = 8</h2>

Step-by-step explanation:

$Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================$

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}$

$\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}$

$4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D$

8 0

3 years ago

What is the solution set for -4 x - 10 ≤ 2?<br><br> x ≤ -3<br> x ≥ -3<br> x ≤ 2<br> x ≥ 2

Lynna [10]

Answer:

x ≥ -3

Step-by-step explanation:

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3 years ago

I need help with my geometry test review.

Alexus [3.1K]

Answer:

is that high school? cuz it looks like 8th or 7th grade

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2 years ago