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2 years ago

5(x-4)=15 find out what x is

Mathematics

2 answers:

irakobra [83]2 years ago

8 0

Answer:

x=7

Step-by-step explanation:

-5*(x-4)-(-15)=0

(0 - 5 • (x - 4)) - -15 = 0

35 - 5x = -5 • (x - 7)

-5 • (x - 7) = 0

Solve : x-7 = 0

Add 7 to both sides of the equation :

x = 7

Digiron [165]2 years ago

4 0

Answer:

Step-by-step explanation:

7-4=3

5×3=15

plz mark brainliest

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What type of transformation has taken place in the picture shown?

nordsb [41]

Answer:

<h2>Reflection and translation.</h2>

Step-by-step explanation:

The picture shows the preimage ABCD and the image A'B'C'D'.

Notice that both images are at the same distance from the x-axis, which implies a reflection across the x-axis. Them, the image was translated 1 units to the left.

Therefore, the right answers are reflection and translation.

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3 years ago

Sick-leave time used by employees of a firm in a course of one month has approximately normal distribution, with a mean of 200 h

Usimov [2.4K]

Answer:

a)0.62% probability that total sick leave for next month will be less than 150 hours.

b) 225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 200, \sigma = \sqrt{400} = 20$

a.Find the probability that total sick leave for next month will be less than 150 hours.

This probability is the pvalue of Z when X = 150. So:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{150 - 200}{20}$

$Z = -2.5$

$Z = -2.5$ has a pvalue of 0.0062.

So there is a 0.62% probability that total sick leave for next month will be less than 150 hours.

b.In planning schedules for next month, how much time should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

This is the value of X when Z has a pvalue of 0.90. So $Z = 1.28$

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 200}{20}$

$X - 200 = 20*1.28$

$X = 225.6$

225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

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3 years ago

A family is preparing backpacks filled with school supplies to donate to children in need. They have 14 pencils and 8 notebooks.

il63 [147K]

Answer:

Step-by-step explanation:

2 is the only common factor between 8 and 14

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3 years ago

Which of the following reasons can be used to justify statement #4 in the proof?

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Answer:

Step-by-step explanation:

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3 0

3 years ago

What is the solution to the system of equations?<br><br> 6x – 9y = 16<br><br> 2x – 3y = 7

kifflom [539]

The first step for solving this problem is to multiply both sides of the bottom equation by -3.
$\left \{ {{6x-9y=16} \atop {-6x + 9y = -21}} \right.$
Add the two equations together.
6x - 9y - 6x + 9y = 16 - 21
Eliminate the opposites.
-9y + 9y = 16 - 21
Remember that the sum of two opposites equals 0,, so the equation becomes the following:
0 = 16 - 21
Calculate the difference on the right side of the equation.
0 = -5
This means that the statement $\left \{ {{6x-9y=16} \atop {2x-3y=7}} \right.$ is false for any value of x and y. That means that the answer to your question is (x,y) ∈ ∅,, or no solution.
Let me know if you have any further questions.
:)

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3 years ago