Answer:
nice!
Step-by-step explanation:
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Answer:
Mark talked on the phone for 120 minutes.
Step-by-step explanation:
18 - 12 = 6
6 ÷ .05 = <u>1</u><u>2</u><u>0</u>
3(2x/5)
Final result :
6x
——
5
Step by step solution :
Step 1 :
x
Simplify —
5
Equation at the end of step 1 :
x
3 • (2 • —)
5
Step 2 :
Final result :
6x
——
5
So, for number 3, its 2. and for number 4 its also 2
