$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}$

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.

5 0

3 years ago

83. 6 in a complex number

grin007 [14]

Answer:

83.6 is a real number

Step-by-step explanation:

Since 83.6 83.6 is a real number, it is the real part (a) of the complex number a+bi a + b i . A real number does not contain any imaginary parts, so the value of b b is 0 0 . The answer is 83.6+0i 83.6 + 0 i

5 0

3 years ago

9-2(7-8)<br><br> Help please

yuradex [85]

9 - 2(7 - 8)
9 - 2(-1)
9 - (-2)
11

6 0

3 years ago

Read 2 more answers

Which symbol(s) represent SI units for temperature? Check all that apply.

Leviafan [203]

Answer:

K of Kelvin