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vagabundo [1.1K]

3 years ago

12

Please answer the correct answer I will give brainliest. Use the graph to write a linear function that relates y to x. y=

1 answer:

Mumz [18]3 years ago

6 0

Answer:

y = 3

Step-by-step explanation:

We need to find the slope. We do so by choosing any two points and dividing the change in the y-coordinates (their difference) by the change in the x-coordinates (their difference). Let's just choose (1, 3) and (0, 3). The slope is: . So, the slope is 0.

We want to write a line in slope-intercept form, which is: y = mx + b, where m is the slope and b is the y-intercept (where the line crosses the y-axis). Here, the slope m = 0. Looking at the graph, we see that the y-intercept is (0, 3), so b = 3. Then, our line is: y = 0x + 3 ⇒ y = 3.

Another note is that this is a horizontal line. One thing to remember is that all horizontal lines have slopes of 0, so their function is simply y = k, where k is a constant through which the line cuts through.

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Graph h(x) =(x-2)(x-4)

sveta [45]

Answer:

Check the image below

Step-by-step explanation:

Some Points that May Help: (2,0), (4,0), (1,3), (5,3), (0,8), and (6,8)

4 0

2 years ago

Sunshine High School claims that 72% of its students complete their homework on a daily basis. Ms. Carter surveyed 80 students a

Ulleksa [173]

Answer: z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

Step-by-step explanation:

let p be the population proportion of students complete their homework on a daily basis.

As per given , we have

p= 0.72

sample size : n= 80

Sample proportion : $\hat{p}=0.60$

Test statistic for proportion:

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

i.e.

$z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(1-0.72)}{80}}}$

i.e.

$z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(0.28)}{80}}}$

That is , z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

6 0

3 years ago

Max wants to make a cute collar and tie fir hus dog. He needs ti cut a 38in fabric into two pieces. The lo ger piece must be 5in

KATRIN_1 [288]

Longer-24 in
Shorter-19in

6 0

3 years ago

A gardener makes a new circular flower bed. The bed is ten feet in diameter. Calculate the circumference and the area of the cir

Mumz [18]

20 is the answer hope it helps :)

4 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago