I need to know the area

The figure shows the movement of a pedestrian as she walks from point B to point E. Write a formula for function d(t) for each s

levacccp [35]

Answer:

crxr utcug UFC tvuyvuyv tvuycrcfgvugvihtc

Step-by-step explanation:

TT good uvjobihcygc r

8 0

2 years ago

Read 2 more answers

Solve x^2 +14x=15 by completing the square

ivanzaharov [21]

Answer:

x = -15 and x = 1

Step-by-step explanation:

Since we have to use the complete the square method, we first need to rewrite the equation in the form $x^{2}+2ax+a^{2}=(x+a)^{2}$ .

This results in $x^{2} + 14x + 7^{2} = 15 + 7^{2}$ .

Next, we simplify the equation to get $x^{2} +14x+7^{2} = 64$ .

Factoring the left side gives us $(x+7)^{2} = 64$ .

Finally we solve the equations: $x+7=\sqrt{64}$ and $x+7=-\sqrt{64}$ .

This gives us x=1, and x=-15

6 0

3 years ago

Read 2 more answers

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago

Help me please I need it

koban [17]

Unfortunately, you inadvertently cut off the instructions for this problem when you photographed it. Could you try again, making certain to include the instructions?

Let me guess: perhaps the instructions are 1) determine the slope of the line passing through the given points, or 2) write the equation of the line passing through the given points.

5 0

3 years ago

Find (−3d2+10d−8)−(7d2−d−6). The difference is .

katovenus [111]

-10d^2 + 11d - 2

To find this, distribute the - to 7d^2 - d - 6.

This will give you a new equation of:

-3d^2 + 10d - 8 -7d^2 + d + 6

Combine like terms to get the answer above.

Hope this helps!

3 0

3 years ago