3X+9=15 WHAT IS THE RESULT?????

The formula for the perimeter of a rectangle is . What is the length of the unknown side of the rectangle below, if the perimete

Troyanec [42]

Answer:

Step-by-step explanation:

P=2l+2w

28=2l+2w

2l=2w-28

l = (2w-28)/2

l =2(w-14)/2

l = w-14

7 0

3 years ago

Use series to verify that <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

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Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

3 years ago

The measure of each angle of a regular octagon is _____ the measure of each exterior angle of a regular hexagon.

VikaD [51]

The answer is "A. greater than" because if the number of edges increase, the measure of each exterior angle increases too!

Hope this helps. :)

6 0

3 years ago

Read 2 more answers

What is −5+(−5r)+10 =-5r+5

VikaD [51]

Answer:

Infinitely many solutions. Each real number is a solution of this equation.

Step-by-step explanation:

-5 + (-5r) + 10 = -5r + 5

5 - 5r = -5r + 5 add 5r to both sides

5 = 5 TRUE

7 0

3 years ago

Read 2 more answers

Best Buy is displaying 15 laptops for a big store sale. The laptops include 6 identical Dells, 4 identical Chromebooks, and 5

Alchen [17]

Answer:

630,630 different arrangements are possible for the given laptops.

Step-by-step explanation:

Total number of laptops = n = 15

Number of identical Dell laptops = 6

Number of identical Chromebooks = 4

Number of identical Mackbooks = 5

We have to find in how many ways can the laptops be arranged. Number of arrangement of objects is calculated using Permutations as the order of objects matter during the arrangement. The formula to calculate the number of possible arrangements when there are similar objects is given as:

$\frac{n!}{a!b!c!...}$

Here n is the total number of objects and a,b, and c represent the number of identical objects. Using the given values we get:

$\frac{15!}{6!4!5!} = 630630$

This means 630,630 different arrangements are possible for the given laptops.

4 0

3 years ago