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ziro4ka [17]
3 years ago
8

Can some help Me pliz​

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0
Can you take a closer picture, I am unable to see it
den301095 [7]3 years ago
6 0
With what?????I don’t see anything only ur text
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What is the answer to 2(x-3)-4(x+3)
Lyrx [107]

Step-by-step explanation:

2 (x-3)-4 (x+3)

  • 2x-6-4x-12
  • -2x-18
  • -2(x+9)
7 0
3 years ago
Read 2 more answers
What is 1+9x3(2x+32)<br> plesse help me if you know it thank you for the help.
hjlf

Answer:

18x^4+288x^3+1

Step-by-step explanation:

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5 0
3 years ago
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Question answer please
Digiron [165]
Equal to a+b on the algebra
6 0
3 years ago
If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
Please solve for M&lt;QTR​
Andru [333]

Answer:

m∠QTR = 98°

Step-by-step explanation:

From the picture attached,

Radii of the circle are TQ and TR measuring equal lengths.

Therefore, ΔTQR is a isosceles triangle.

Opposite angles of the equal sides will be equal in measure.

m∠RQT = m∠TRQ = 41°

By angle sum theorem,

m∠RQT + m∠TRQ + m∠QTR = 180°

41° + 41° + m∠QTR = 180°

m∠QTR = 180° - 82°

              = 98°

Therefore, m∠QTR = 98°

7 0
3 years ago
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